Both are metals and are good conductors of electricity and heat.
Answer:
x = 0.67 m
Explanation:
For this problem, let's use the projectile launch equations, as the jug goes through the bar, it comes out with horizontal speed vx = 1.3 m / s, which does not decrease as there is no friction.
Let's find the time or it takes to get to the floor
y = y₀ + v_{oy} - ½ g t²
in this case I go = 0 and when I get to the floor y = 0
0 = y₀ + 0 - ½ g t²
t² = 2y₀ / g
t² = 2 1.3 / 9.8 = 0.2653
t = 0.515 s
now let's find the distance traveled in this time
x = vx t
x = 1.3 0.515
x = 0.6696 m
x = 0.67 m
That would be the Russian chemist Dmitri Mendeleev
This is a question volumetric flow rate.
In 1 second, water rises with 0.4 in.
Additionally,
Volume filled in 1 second = A*0.4, A = surface area of the circular cylinder.
Where,
A = πR^2 = π*3^2 = 9π in^2
Therefore,
Volumetric flow rate = 9π*0.4 = 11.31 in^3/s
In terms of liters/s,
1 in^3 = 0.0163871 litres
Then,
11.31 in^3/s = 11.31*0.0163871 ≈ 0.19 l/s
Answer:
(a). The electric potential at 1.650 cm is .
(b). The electric potential at 2.81 cm is .
Explanation:
Given that,
Radius of sphere R=2.81 cm
Charge = +2.35 fC
Potential at center of sphere
(a). We need to calculate the potential at a distance r = 1.60 cm
Using formula of potential difference
The electric potential at 1.650 cm is .
(b). We need to calculate the potential at a distance r = R
Using formula of potential difference
The electric potential at 2.81 cm is .
Hence, This is the required solution.