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CaHeK987 [17]
3 years ago
11

The set of conditions 1.00 atm pressure and 0.00 oc is defined as ________.

Chemistry
2 answers:
Brums [2.3K]3 years ago
7 0
Hello!

The answer for the blank is pressure

Hope it helps!`
r-ruslan [8.4K]3 years ago
5 0
<span>The set of conditions 1.00 atm pressure and 0.00 oc is defined as pressure.</span>
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Glycolic acid, which is a monoprotic acid and a constituent in sugar cane, has a pKa of 3.9. A 25.0 mL solution of glycolic acid
slava [35]

Answer:

pH of resulting solution = 7.98

Explanation:

The balanced equation  

HA + NaOH - Na+ + A- + H2O

Number of moles of A = Number of moles of HA  = Number of moles of NaOH

= 35.8/1000 * 0.020 = 0.000716 mol

Initial concentration of A = 0.000716/0.0608 = 0.01178 M

pKb = 14 – pKa = 14 -3.9 = 10.1

Kb = 10^{-Kb} = 10^{-10.1} = 7.943 * 10^-11

Kb = [HA][OH-]/[A-]

Kb = a^2/(0.01178 -a) = 7.943 * 10^-11

a^2 + 7.943 * 10^-11 a – 9.357 * 10^-13 = 0

a = 9.673 * 10^-7

OH- = a = 9.673 * 10^-7 M

pOH = -log [OH-] = -log (9.673 * 10^-7) = 6.02

pH = 14-6.02 = 7.98

8 0
2 years ago
What is an example of entropy from everyday life?
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One of the greatest examples of entropy working in everyday life is the fact that a messy room is the norm. So if you clean your room it will likely become messy over a period of time, and work will have to be put in to make it orderly again.
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Glycerol boils at a high temperature than water. What does this indicate about the attractive forces of glycerol?
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Glycerol attractive forces are great than water. The harder to break, the more energy is needed.
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Risk is the ______ of a negative outcome
Vera_Pavlovna [14]
Is there any  choices or is this a fill in the blank question?

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3 years ago
By the reaction of carbon &amp; oxygen , a mixture of CO &amp;CO2 is obtained. What is the composition by mass of the mixture ob
Hatshy [7]
M(O₂)=20g
M(O₂)=32.0 g/mol
n(O₂)=20/32.0=0.625 mol

m(C)=12 g
M(C)=12.0 g/mol
n(C)=12/12.0=1.0 mol

   2C     +     O₂      →    2CO
1 mol    0.625 mol        1 mol
         0.625-0.5=0.125 mol

      2CO    +         O₂       →        2CO₂
0.250 mol       0.125 mol       0.250 mol

n(CO)=1 mol - 0.250 mol = 0.750 mol
M(CO)=28.0 g/mol
m(CO)=0.750*28.0=21.0 g

n(CO₂)=0.250 mol
M(CO₂)=44.0 g/mol
m(CO₂)=0.250*44.0=11.0 g
4 0
3 years ago
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