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vlada-n [284]
3 years ago
9

For a particular reaction, ΔH∘=67.7 kJ/mol and ΔS∘=126.9 J/(mol⋅K). Assuming these values change very little with temperature, a

t what temperature does the reaction change from nonspontaneous to spontaneous in the forward direction?T= K Is the reaction in the forward direction spontaneous at temperatures greater than or less than the calculated temperature?greater thanless than
Chemistry
1 answer:
Sav [38]3 years ago
3 0

Answer:

When T > 533.5K, the reaction is spontaneous in the forward reaction.

When T < 533.5K, the reaction is nonspontaneous

Explanation:

Using the equation:

ΔG = ΔH - TΔS

<em>Where T is absolute temperature</em>

<em />

The ΔG < 0 indicates nonspontaneus reaction, ΔG > 0 indicates spontaneous reaction.

That means:

0J/mol = 67700J/mol - T*126.9J/molK

T*126.9J/molK = 67700J/mol

T = 533.5 K

That means:

<h3>When T > 533.5K, the reaction is spontaneous in the forward reaction.</h3><h3>When T < 533.5K, the reaction is nonspontaneous</h3>

<em />

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