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tatiyna
3 years ago
10

How much power is used by a 6.0-V flashlight battery that draws 0.5 A of current

Physics
1 answer:
igor_vitrenko [27]3 years ago
3 0

Answer:

Power=3watts

Explanation:

Current=0.5A

Voltage=6v

Power=current x voltage

Power=0.5 x 6

Power=3watts

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Find the frequency, if the amplitude of a 3000g object in simple harmonic motion is 1000cm and the maximum speed of the object i
Oksana_A [137]

Answer:

A = 10 m     amplitude

m = 3 kg     mass of object

Vm = 5 m/s

w A = Vm      where w = omega

w = 2 * pi * f

2 * pi * f  10 = 5

f = 5 / (20 * pi)  = .0796 / sec

7 0
3 years ago
A ball is thrown into the air with 100 J of kinetic energy, which is transformed to gravitational potential energy
goblinko [34]

Answer:

Air resistance

Explanation:

Despite the law of conservation of energy stating that energy can neither be created nor destroyed but can only be transformed from one state to another, some energy is usually lost in the process of transformation and its majorly attributed to frictional loss. Friction opposes normal movement hence in air, air resistance tends to reduce the original energy compared to the initial. That is why the final energy in this case is slightly less than the original energy.

3 0
4 years ago
If a negatively charged particle enters a region of uniform magnetic field which is perpendicular to the particle's velocity, wi
lys-0071 [83]

Answer:

Same

Explanation:

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3 0
3 years ago
Newton's First and Second Laws of Motion:Question 3Kepler-10b, the first confirmed terrestrial extrasolar planet, is about 564 l
OleMash [197]

Answer:

F = 85696.5 N = 85.69 KN

Explanation:

In this scenario, we apply Newton's Second Law:

Unbalanced\ Force = ma\\Upthrust - Weight\ of\ Space\ Craft = ma\\F - W = ma\\F - mg = ma\\F = m(g + a)\\

where,

F = Upthrust = ?

m = mass of space craft = 5000 kg

g = acceleration due to gravity on surface of Kepler-10b = (1.53)(9.81 m/s²)

g = 15.0093 m/s²

a = acceleration required = 2.13 m/s²

Therefore,

F = (5000\ kg)(15.0093\ m/s^{2} + 2.13\ m/s^{2})\\

<u>F = 85696.5 N = 85.69 KN</u>

8 0
3 years ago
The _______ is the temperature to which air must be cooled at constant pressure to reach saturation.
Dafna1 [17]
The answer is the dew point
8 0
3 years ago
Read 2 more answers
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