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3 years ago

How many joules are needed to melt 50 g of ice at 0°C?

Chemistry

1 answer:

Alexeev081 [22]3 years ago

6 0

Answer:

You need the Delta H fusion for water. Multiply that by 50 grams. Then multiply 50 g x 4.184 x 65 to get joules to raise water to 65 degrees. Add these values together to get total joules.

Explanation:

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How many atoms are in .47 moles of argon

lesantik [10]

Answer:

$\large \boxed {2.8 \times 10^{23}\text{ atoms Ar}}$

Explanation:

$\text{Atoms of Ar} = \text{0.47 mol Ar} \times \dfrac{ 6.022 \times 10^{23}\text{ atoms Ar}}{\text{1 mol Ar}}\\\\= \large \boxed {\mathbf{2.8 \times 10^{23}}\textbf{ atoms Ar}}$

3 0

3 years ago

he rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy . If the rate c

Leya [2.2K]

The question is incomplete, here is the complete question:

The rate constant of a certain reaction is known to obey the Arrhenius equation, and to have an activation energy Ea = 71.0 kJ/mol . If the rate constant of this reaction is 6.7 M^(-1)*s^(-1) at 244.0 degrees Celsius, what will the rate constant be at 324.0 degrees Celsius?

<u>Answer:</u> The rate constant at 324°C is $61.29M^{-1}s^{-1}$

<u>Explanation:</u>

To calculate rate constant at two different temperatures of the reaction, we use Arrhenius equation, which is:

$\ln(\frac{K_{324^oC}}{K_{244^oC}})=\frac{E_a}{R}[\frac{1}{T_1}-\frac{1}{T_2}]$

where,

$K_{244^oC}$ = equilibrium constant at 244°C = $6.7M^{-1}s^{-1}$

$K_{324^oC}$ = equilibrium constant at 324°C = ?

$E_a$ = Activation energy = 71.0 kJ/mol = 71000 J/mol (Conversion factor: 1 kJ = 1000 J)

R = Gas constant = 8.314 J/mol K

$T_1$ = initial temperature = $244^oC=[273+244]K=517K$

$T_2$ = final temperature = $324^oC=[273+324]K=597K$

Putting values in above equation, we get:

$\ln(\frac{K_{324^oC}}{6.7})=\frac{71000J}{8.314J/mol.K}[\frac{1}{517}-\frac{1}{597}]\\\\K_{324^oC}=61.29M^{-1}s^{-1}$

Hence, the rate constant at 324°C is $61.29M^{-1}s^{-1}$

8 0

3 years ago

Good day pleases help

klemol [59]

I can’t see the choices can you take another picture of this assignment please so i can help you

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3 years ago

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Some fruits and vegetables are preserved by pickling them. Nandini got confused

stepan [7]

Answer:

Explanation:

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3 years ago

A 0.300 m solution of hcl is prepared by adding some 1.50 m hcl to a 500 ml volumetric flask and diluting to the mark with deion

liberstina [14]

In dilution we add distilled water to decrease the concentration of required sample from high concentration to lower concentration
The law used for dilution:
M₁V₁]Before dilution = M₂V₂] After dilution
M₁ = 1.5 M
V₁ = ?
M₂ = 0.3 M
V₂ = 500 ml
1.5 * V₁ = 0.3 * 500 ml
so V₁ = 100 ml and it completed to 500 ml using 400 ml deionized water

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3 years ago