A large crate is pushed across the floor with an effort of 45 Newtons. The box is pushed a distance of 3.5 meters. How much work
1 answer:
Answer:
Explanation:
Work is equal to the product of force and distance.
The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.
Substitute the values into the formula.
Multiply.
- 1 Newton meter is equal to 1 Joule
- Our answer of 157.5 N*m equals 157.5 J
<u>157.5 Joules </u> of work are done on the crate.
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(a) +9.30 kg m/s
The impulse exerted on an object is equal to its change in momentum:
where
m is the mass of the object
is the change in velocity of the object, with
v = final velocity
u = initial velocity
For the volleyball in this problem:
m = 0.272 kg
u = -12.6 m/s
v = +21.6 m/s
So the impulse is
(b) 155 N
The impulse can also be rewritten as
where
F is the force exerted on the volleyball (which is equal and opposite to the force exerted by the volleyball on the fist of the player, according to Newton's third law)
is the duration of the collision
In this situation, we have
So we can re-arrange the equation to find the magnitude of the average force:
The acceleration of the sled will be 1.30 m/s². Force is defined as the product of mass and acceleration.
<h3>What is force?</h3>Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
Given data;
m(mass of sled)=8 kg
Θ is the inclination of force= 50°
Force of friction,f=2.4 N.
The applied force at the given angle is resolved into the two-component as;
The net vertical force is zero;
From Newton's second law the net force as;
Hence, the acceleration of the sled will be 1.30 m/s².
To learn more about the force refer to the link;
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