Negative symbol which means that gain of electron.
I not sure about the answer sorry!! if you will get wrong in your book
Answer : The pH of 0.289 M solution of lithium acetate at 
is 9.1
Explanation :
First we have to calculate the value of 
.
As we know that,
where,
= dissociation constant of an acid = 
= dissociation constant of a base = ?
= dissociation constant of water = 
Now put all the given values in the above expression, we get the dissociation constant of a base.
Now we have to calculate the concentration of hydroxide ion.
Formula used :
![[OH^-]=(K_b\times C)^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%28K_b%5Ctimes%20C%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
where,
C is the concentration of solution.
Now put all the given values in this formula, we get:
![[OH^-]=(5.5\times 10^{-10}\times 0.289)^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D%285.5%5Ctimes%2010%5E%7B-10%7D%5Ctimes%200.289%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
![[OH^-]=1.3\times 10^{-5}M](https://tex.z-dn.net/?f=%5BOH%5E-%5D%3D1.3%5Ctimes%2010%5E%7B-5%7DM)
Now we have to calculate the pOH.
![pOH=-\log [OH^-]](https://tex.z-dn.net/?f=pOH%3D-%5Clog%20%5BOH%5E-%5D)
Now we have to calculate the pH.
Therefore, the pH of 0.289 M solution of lithium acetate at is 9.1
Answer:
B. 0.7%
Explanation:
Given data:
Actual boiling point = 82.5°C
Experimental boiling point = 83.1°C
Percent error = ?
Solution:
Formula:
Percent error = ( actual value - experimental value / actual value )×100
by putting values,
Percent error = (82.5°C - 83.1 °C /82.5°C) × 100
Percent error = 0.007 × 100
Percent error = 0.7 %
Negative sign shows that experimental value is greater than accepted value. It can not written in result.
Answer:
H2O
Explanation:
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