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3 years ago

8

A distance of 0.002 m separates two objects of equal mass. If the gravitational force between them is

1 answer:

Alika [10]3 years ago

6 0

Answer: 24.97 kg

Explanation:

The gravitational force between two objects of masses M1, and M2 respectively, and separated by a distance R, is:

F = G*(M1*M2)/R^2

Where G is the gravitational constant:

G = 6.67*10^-11 m^3/(kg*s^2)

In this case, we know that

R = 0.002m

F = 0.0104 N

and that M1 = M2 = M

And we want to find the value of M, then we can replace those values in the equation to get

0.0104 N = (6.67*10^-11 m^3/(kg*s^2))*(M*M)/(0.002m)^2

(0.0104 N)*(0.002m)^2/(6.67*10^-11 m^3/(kg*s^2)) = M^2

623.69 kg^2 = M^2

√(623.69 kg^2) = M = 24.97 kg

This means that the mass of each object is 24.97 kg

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Answer:

The metal will melt but their will be no change in temperature.

Explanation:

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<u>On supplying heat, the metal's temperature will not change as the heat will be required as enthalpy of condensation to melt the solid to liquid at the melting temperature.</u>

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3 years ago

Two metal spheres of different sizes are charged such that the electric potential is the same at the surface of each. Sphere A h

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Answer:

Explanation:

Given

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$R_A=2R_B$

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(b)Ratio of $\frac{E_B}{E_A}$

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3 years ago

15. Calculate The coefficient of kinetic friction be-

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Answer:

Wt = 26.84 [N]

Explanation:

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The friction force is defined as the product of the normal force by the coefficient of friction.

f = N*μ

where:

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f = friction force [N]

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f = 72*9.81*0.21

f = 148.32 [N]

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Wt = total work [J] (units of Joules)

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Answer:

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