Question

Diagram shows the velocity time graph for a particle moving in 16 seconds.

Answer 1

Answer:

The detailed calculations are shown below;

Explanation:

a)The maximum acceleration of the particle:

  It is seen that the maximum change in velocity is at the time between 8s to 10s.

              Maximum acceleration: $\frac{V}{t}$

                                                    = $\frac{20}{2}$

                                                    = 10 m/$s^{2}$

b) The deceleration of the particle

          The velocity of particle is decreased after 10s so,

                     deceleration = - $\frac{40}{6}$

                                           = - 6.67 m/$s^{2}$

c)The total distance traveled by the particle = Area under the curve

                               = $\frac{1}{2}$* 4*20 + 4*20 +  $\frac{1}{2}$* 2*20+ 2*20+ $\frac{1}{2}$* 40*16

                                                       = 290 m

d)The average velocity of the particle = $\frac{Area under the curve}{Total time}$

                                                               = $\frac{290}{16}$

                                                               = 18.12 m/s