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harina [27]
3 years ago
13

The following reaction proceeds at a rate such that 3 mole of A is consumed per minute. Given this, how many moles of C are prod

uced per minute? 2A+2B→4C
Chemistry
1 answer:
Dovator [93]3 years ago
5 0

Answer:

6 mol/min

Explanation:

2A+2B→4C

The relationship between the reactants and products of this equation is given by;

1/2 -d[A]/dt = 1/2 -d[B]/dt = 1/4 d[C]/dt

Our focus is on A and C

From the question;

d[A]/dt = 3mol/min

We have;

1/2 (3) = 1/4 d[C]/dt

d[C]/dt = 4/2 * 3 = 6 mol/min

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Vladimir79 [104]

C. 1.0 M Al2O3 would be the best answer

8 0
2 years ago
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During translation, the new polypeptides are often directed to specific parts of the cell by the presence or absence of short se
kotegsom [21]

Answer:

The correct option is b. an amino-terminal signal

Explanation:

A polypeptide that will eventually fold to become an ion channel protein, it means a kind of integral membrane protein, has an amino terminal signal that indicates its delivery to endoplasmic reticulum (ER) and then to the membrane. This type of signal usually consist in a nucleus of 6 to 12 aminoacids and one or more basic aminoacids. Once the polypeptide enters the ER, this signal is removed.

6 0
3 years ago
You have 8 moles of a gas at 250 K in a 6 L container. What is the pressure of the gas? Show your work
Bogdan [553]

Hello:

In this case, we will use the Clapeyron equation:

P = ?

n = 8 moles

T = 250 K

R = 0.082 atm.L/mol.K

V = 6 L

Therefore:

P * V = n *  R * T

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P = 164 / 6

P = 27.33 atm


Hope that helps!

7 0
3 years ago
Estimate your de Broglie wavelength when you are running. (For this problem use h = 10^−34 in SI units and 1 lb is equivalent to
AlekseyPX

Answer:

A. your running speed 1.5 m/s

B. your mass 70 kg

C. your de Broglie wavelength 6.32x10^{-36}m

Explanation:

Hello there!

In this case, since the equation for the calculation of the Broglie wavelength is:

\lambda =\frac{h}{m*v}

We can assume a running speed of about 1.5 m/s and a mass of 70 kg, so the resulting Broglie wavelength is:

\lambda =\frac{6.626x10^{-34}kg\frac{m}{s} }{70kg*1.5\frac{m}{s} }\\\\\lambda =6.32x10^-36m

Best regards!

7 0
3 years ago
Which one of the following atoms has the largest radius? Ова Осо OCa
RUDIKE [14]

Answer:

Ba

Explanation:

<u>The elements  Calcium ( Ca ) and Cobalt ( Co ) , are both present in the same period , and across the period the atomic radius decreases from left to right , since , the atomic number increases , so the electrons increases , which in turns increases the effective nuclear charge , and hence the size decreases , </u>

Therefore ,

Calcium will have bigger atomic radii as compared to Cobalt .

Now,

<u>The elements Barium ( Ba ) and Calcium ( Ca ) are , both are present in the same group , and down the group , atomic radii increases , since , as going down the group , the atomic number increase , so the shells increases , hence the size increases .</u>

Therefore , the atom with the largest radii is Barium .

7 0
3 years ago
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