<u>Answer:</u> The mass of potassium sulfate that can be produced is 73.88 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of KOH = 23.8 g
Molar mass of KOH = 56.1 g/mol
Putting values in equation 1, we get:
![\text{Moles of KOH}=\frac{23.8g}{56.1g/mol}=0.424mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20KOH%7D%3D%5Cfrac%7B23.8g%7D%7B56.1g%2Fmol%7D%3D0.424mol)
The chemical equation for the reaction of KOH and potassium hydrogen sulfate follows:
![KHSO_4+KOH\rightarrow K_2SO_4+H_2O](https://tex.z-dn.net/?f=KHSO_4%2BKOH%5Crightarrow%20K_2SO_4%2BH_2O)
As, potassium hydrogen sulfate is present in excess. It is considered as an excess reagent.
KOH is considered as a limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 mole of KOH produces 1 mole of potassium sulfate
So, 0.424 moles of KOH will produce =
of potassium sulfate
Now, calculating the mass of potassium sulfate from equation 1, we get:
Molar mass of potassium sulfate = 174.26 g/mol
Moles of potassium sulfate = 0.424 moles
Putting values in equation 1, we get:
![0.424mol=\frac{\text{Mass of potassium sulfate}}{174.26g/mol}\\\\\text{Mass of potassium sulfate}=(0.424mol\times 174.26g/mol)=73.88g](https://tex.z-dn.net/?f=0.424mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20potassium%20sulfate%7D%7D%7B174.26g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20potassium%20sulfate%7D%3D%280.424mol%5Ctimes%20174.26g%2Fmol%29%3D73.88g)
Hence, the mass of potassium sulfate that can be produced is 73.88 grams