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4 years ago

Please answer correctly !!!!!!!! Will mark brainliest !!!!!!!!!!!!

Mathematics

2 answers:

Debora [2.8K]4 years ago

8 0

Drag the numbers together one at a time then drag the 2 (x) together you should end up with -2x+7+y

pogonyaev4 years ago

6 0

2 - x + 6 - 1 + y - x

Answer: 7 - 2x + y

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An object is dropped from a small plane. As the object falls, its distance, d, above the ground after t seconds, is given by the

DedPeter [7]

The inequality can be used to find the interval of time taken by the object to reach the height greater than 300 feet above the ground is:

$d = -16t^2 + 1000$

Solution:

The object falls, its distance, d, above the ground after t seconds, is given by the formula:

$d = -16t^2 + 1000$

To find the time interval in which the object is at a height greater than 300 ft

Frame a inequality,

$-16t^2 + 1000 > 300$

Solve the inequality

Subtract 1000 from both sides

$-16t^2 + 1000 - 1000 > 300 - 1000\\\\-16t^2 > -700$

$16t^2 < 700\\\\Divide\ both\ sides\ by\ 16\\\\t^2 < \frac{700}{16}\\\\Take\ square\ root\ on\ both\ sides\\\\t < \sqrt{\frac{700}{16}}\\\\t < \pm 6.61$

Time cannot be negative

Therefore,

t < 6.61

And the inequality used is: $-16t^2 + 1000>300$

6 0

3 years ago

Plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz please please please please please please helpppppppppWill give brainliest to right answer

Law Incorporation [45]

A circle with a radius of 4cm sits inside a circle with a radius of 11cm
What is the area of the shaded region?
Round your final answer to the nearest hundredth.

Answer: 329.86 cm

6 0

3 years ago

After a reflection, can A=A'?

motikmotik

NO It can not!

Reason: the reason is because since both are the same , it will equal the mostly 0! So it wouldn’t make sense. So no!

Hoped I help mark brainly it would help me a lot!

4 0

3 years ago

Find the perimeter of a square with a side length of 4x

julia-pushkina [17]

Answer: $16x^{2}$

Step-by-step explanation:

4 0

3 years ago

1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.

kkurt [141]

1. The values of p and q are: p=31 and q= 4

2. B(11, 29/5)

Further explanation:

1. L(15. 1) is the midpoint of the straight line joining point (p. - 2) to point D(-1. q) find p and q.

Given:

M = (15. 1)

(x1, y1) = (p, -2)

(x2, y2) = (-1, q)

The formula for mid-point is:

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M \\Putting\ the\ values\\(\frac{p-1}{2} , \frac{-2+q}{2}) = (15,1)\\Putting\ realtive\ values\ equal\\\frac{p-1}{2} = 15\\p-1 = 15(2)\\p-1 = 30\\p = 30+1\\p = 31\\\frac{-2+q}{2} =1\\-2+q = 2(1) \\-2+q = 2\\q = 2+2 \\q =4$

Hence,

p=31

q=4

2. M is the midpoint of the straight line joining point A (3. 1/5) to point B.If m has coordinates (7. 3), find the coordinates of B.

Here,

(x1,y1) = (3, 1/5)

(x2, y2) = ?

M(x,y) = (7,3)

Putting values in the formula of mid-point

$(\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2}) = M\\(\frac{3+x_2}{2} , \frac{1/5+y_2}{2}) = (7,3)\\\frac{3+x_2}{2} = 7\\3+x_2 = 7*2\\3+x_2 = 14\\x_2 = 14-3\\x_2 = 11\\\frac{\frac{1}{5}+y_2}{2} = 3\\{\frac{1}{5}+y_2} = 3*2\\{\frac{1}{5}+y_2} = 6\\y_2 = 6 - \frac{1}{5}\\y_2 = \frac{30-1}{5}\\y_2 = \frac{29}{5}$

So, the coordinates of point B are (11, 29/5) .

Keywords: Finding mid-point, Finding coordinates through mid-point

Learn more about coordinate geometry at:

#LearnwithBrainly

6 0

4 years ago