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3 years ago

Which title best fits Rahma's note

Physics

2 answers:

Alik [6]3 years ago

5 0

Answer:diffusion

Explanation: it right

Semenov [28]3 years ago

4 0

Answer:

diffusion is the answer.

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An astronaut is drifting away from his spaceship. how can he return, using an aerosol spray?

beks73 [17]

The astronaut should shoot the aerosol spray in the opposite direction of where the astronaut is going to return back to the spaceship. This is in accordance to Newton’s Thrid Law, every action has an equal and opposite reaction.

Hope this helps you out!

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2 years ago

What is the function of mitocondria? Pls Anyone

Anastasy [175]

Explanation:

Mitochondria is called the 'power house' because It is the site for respiration. It is also responsible for conversation of food to usable energy.

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2 years ago

Read 2 more answers

What kind of radiation is emitted in the following nuclear reaction

miv72 [106K]

Beta emission is occurring in the given nuclear reaction.

Answer: Option B

<u>Explanation:</u>

In this equation, the reactant is the Thorium atom, which is reduced to palladium. As the atomic number get decreased by one, so an electron will be emitted. This process of emission of electrons by radiation or decaying the reactant nuclei to form a new product nuclei is termed as beta emission.

So, the electrons are generally termed as beta particles while the positrons are termed as positive beta particles. So this is a kind of radioactive reactions where the reactant changes to new element by releasing an electron and thus there is a change in the atomic number of the product by one.

4 0

3 years ago

A roller coaster car is traveling at a constant 3 m/s when it reaches a downward slope. On the slope, the car accelerates at a c

kirill [66]

Answer:

Velocity of the car at the bottom of the slope: approximately $20.3\; \rm m \cdot s^{-2}$ .

It would take approximately $3.9\; \rm s$ for the car to travel from the top of the slope to the bottom.

Explanation:

The time of the travel needs to be found. Hence, make use of the SUVAT equation that does not include time.

Let $v$ denote the final velocity of the car.
Let $u$ denote the initial velocity of the car.
Let $a$ denote the acceleration of the car.
Let $x$ denote the distance that this car travelled.

$v^2 - u^2 = 2\, a\cdot x$ .

Given:

$u = 3\; \rm m \cdot s^{-1}$ .
$a = 4.5\; \rm m \cdot s^{-2}$ .
$x = 45\; \rm m$ .

Rearrange the equation $v^2 - u^2 = 2\, a\cdot x$ and solve for $v$ :

$\begin{aligned}v &= \sqrt{2\, a \cdot x + u^2} \\ &= \sqrt{2 \times 4.5\; \rm m \cdot s^{-2} \times 45\; \rm m + \left(3\; \rm m \cdot s^{-1}\right)^{2}} \\ &\approx 20.3\; \rm m \cdot s^{-1}\end{aligned}$ .

Calculate the time required for reaching this speed from $u = 3\; \rm m \cdot s^{-1}$ at $a = 4.5\; \rm m \cdot s^{-2}$ :

$\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{20.3\; \rm m \cdot s^{-1} - 3\; \rm m \cdot s^{-1}}{4.5\; \rm m \cdot s^{-2}} \approx 3.9\; \rm m \cdot s^{-1}\end{aligned}$ .

3 0

3 years ago

if the emission lines in the spectrum of one object are more strongly blueshifted than those from a second object, then the firs

Lelu [443]

Answer:

Toward us faster than the second object

Explanation:

6 0

2 years ago