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3 years ago

Which title best fits Rahma's note

Physics

2 answers:

Alik [6]3 years ago

5 0

Answer:diffusion

Explanation: it right

Semenov [28]3 years ago

4 0

Answer:

diffusion is the answer.

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Calculate the percentage increase in speed of the cyclist when the power output changes from 200 W to 300 W.

Rom4ik [11]

Answer:

50%

Explanation:

Given

Initial power = 200W

Final power = 300W

Increment = 300 - 200 = 100W

percentage increase = increment/initial power * 100

percentage increase = 100/200 * 100%

percentage increase = 0.5 * 100

percentage increase = 50%

Hence the percentage increase in speed is 50%

6 0

3 years ago

A 30 cm scale has one end broken. The mark at the broken end is 2.6 cm. How would you use it to measure the length of your penci

lidiya [134]

Answer:

the mark of the broken end is 2.6 cm so, we use the scale from the next full mark i.e. 3cm

Explanation:

we now measure the length of the pencil by keeping the 3 cm mark of the scale at it's left end.

The 3 cm value is then subtracted from the scale reading at the right side end of the pencil to obtain the correct length of the pencil. ✏️

(i i ) place the scale in the contact with object along it's length

(2) Your eyes must be exactly in front of the point where the measurements to be taken.

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6 0

3 years ago

Which of the following is an SI base unit for measuring length?

irina [24]

Meters it the SI unit for measuring length.

6 0

3 years ago

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A block of a plastic material floats in water with 42.9% of its volume under water. What is the density of the block in kg/m3?

adell [148]

To solve this problem we will apply the principle of buoyancy of Archimedes and the relationship given between density, mass and volume.

By balancing forces, the force of the weight must be counteracted by the buoyancy force, therefore

$\sum F = 0$

$F_b -W = 0$

$F_b = W$

$F_b = mg$

Here,

m = mass

g =Gravitational energy

The buoyancy force corresponds to that exerted by water, while the mass given there is that of the object, therefore

$\rho_w V_{displaced} g = mg$

Remember the expression for which you can determine the relationship between mass, volume and density, in which

$\rho = \frac{m}{V} \rightarrow m = V\rho$

In this case the density would be that of the object, replacing

$\rho_w V_{displaced} g = V\rho g$

Since the displaced volume of water is 0.429 we will have to

$\rho_w (0.429V) = V \rho$

$0.429\rho_w= \rho$

The density of water under normal conditions is $1000kg / m ^ 3$ , so

$0.429(1000) = \rho$

$\rho = 429kg/m^3$

The density of the object is $429kg / m ^ 3$

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3 years ago

You have 2 minutes to get to PE from science class before you get a tardy. If PE is 100m away and you walk at a speed of 1.1m/s

mart [117]

Answer:

Explanation:

4 0

3 years ago

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