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Allushta [10]
3 years ago
9

Which title best fits Rahma's note

Physics
2 answers:
Alik [6]3 years ago
5 0

Answer:diffusion

Explanation: it right

Semenov [28]3 years ago
4 0

Answer:

diffusion is the answer.

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The cha-cha-cha, is a dance of Cuban origin. It is danced to the music of the same name introduced by Cuban composer and violinist Enrique Jorrin in the early 1950s. This rhythm was developed from the danzón-mambo

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The force of kinetic friction between a box sliding on a surface depends on the ____ .
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Answer: speed of the box

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If F1 is the magnitude of the force exerted
aleksandrvk [35]

Answer: 3. F1 = F2

Explanation:

According to <u>Newton's law of Gravitation</u>, the force F exerted <u>between two bodies</u> or objects of masses M and m and separated by a distance r is equal to the product of their masses divided by the square of the distance:  

F=G\frac{Mm}{r^2} (1)

Where Gis the gravitational constant

Now, in the especific case of the Earth and the satellite, where the Earth has a mass M and satellite a mass m, being both separated a distance r, the force exerted  by the Earth on the satellite is:

F1=G\frac{Mm}{r^2}   (2)

And the force  exerted by the satellite on the Earth is:

F2=G\frac{Mm}{r^2}   (3)

As we can see equations (2) and (3) are equal, hence the magnitude of the gravitational force is the same for both:

F1=F2

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3 years ago
If argon could exist as a solid, what would best represent the speed through solid argon?
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Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light.
pogonyaev

Complete Question

Due to blurring caused by atmospheric distortion, the best resolution that can be obtained by a normal, earth-based, visible-light telescope is about 0.3 arcsecond (there are 60 arcminutes in a degree and 60 arcseconds in an arcminute).Using Rayleigh's criterion, calculate the diameter of an earth-based telescope that gives this resolution with 700 nm light

Answer:

The diameter is  D = 0.59 \  m    

Explanation:

From the question we are told that

      The best resolution is  \theta  =  0.3 \  arcsecond

       The  wavelength is  \lambda  =  700 \  nm =  700 *10^{-9 } \  m

       

Generally the

         1 arcminute  = >  60 arcseconds

=>      x arcminute =>   0.3 arcsecond

So

       x =  \frac{0.3}{60 }

=>    x = 0.005 \  arcminutes

Now

         60 arcminutes  =>  1 degree

          0.005 arcminutes = >  z degrees  

=>       z =  \frac{0.005}{60 }

=>      z =  8.333 *10^{-5}  \ degree

Converting to radian  

           \theta  = z =  8.333 *10^{-5}  * 0.01745 = 1.454 *10^{-6} \  radian

Generally the resolution is mathematically represented as

            \theta  =  \frac{1.22 *  \lambda  }{ D}

=>    D =  \frac{1.22 * \lambda }{\theta }

=>     D =  \frac{1.22 * 700 *10^{-9} }{ 1.454 *10^{-6} }    

=>     D = 0.59 \  m    

4 0
3 years ago
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