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Sunny_sXe [5.5K]
4 years ago
14

Why doesn't glue stick to the inside of the bottle?

Engineering
1 answer:
Galina-37 [17]4 years ago
6 0

Answer:

Explanation:

When white is inside a , there's not enough air inside the to cause the water to

to make the sticky. Basically, the protects the from the air and keeps the runny.

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Answer pleaseeeee quick​
mojhsa [17]
Bending effect!! Whenever the orientation of the diffracting planes changes when the diffracting planes bend, the contrast changes
7 0
3 years ago
Read the first paragraph of the article.
Paladinen [302]

Answer:

i think it is A, i could not really understand your question.

Explanation:

just a question

(wheres the article?)

5 0
3 years ago
Air at 40°C flow steadily through the pipe shown in Fig. 1 below. If P1 = 40 kPa (gage), P2 = 10 kPa (gage), D = 3d, Patm ≅ 100
Dafna1 [17]

Based on the average velocity at section 2, and the absolute pressures at both sectors, the average speed at section 1 is 2.226 m/s.

<h3>What is the average speed at section 1?</h3>

Density at P₁:

= (40 + 100) / (0.287 x  (40 + 273))

= 1.5585 kg/m³

Density at P₂:
= (10 + 100) / (0.287 x  (40 + 273))

= 1.2245 kg/m³

The average speed at section 1 is:

= (Density at P₂ x d² x 25.5) / (Density at P₁ x 9d²)

= 2.226 m/s

Find out more on average velocity at brainly.com/question/17444459.

#SPJ1

8 0
3 years ago
Air enters a 34 kW electrical heater at a rate of 0.8 kg/s with negligible velocity and a temperature of 60 °C. The air is disch
Flura [38]

Answer:

79 kW.

Explanation:

The equation for enthalpy is:

H2 = H1 + Q - L

Enthalpy is defined as:

H = G*(Cv*T + p*v)

This is specific volume.

The gas state equation is:

p*v = R*T (with specific volume)

The specific gas constant for air is:

287 K/(kg*K)

Then:

T1 = 60 + 273 = 333 K

T2 = 200 + 273 = 473 K

p1*v1 = 287 * 333 = 95.6 kJ/kg

p2*v2 = 287 * 473 = 135.7 kJ/kg

The Cv for air is:

Cv = 720 J/(kg*K)

So the enthalpies are:

H1 = 0.8*(0.72 * 333 + 95.6) = 268 kW

H2 = 0.8*(0.72 * 473 + 135.7) = 381 kW

Ang the heat is:

Q = 34 kW

Then:

H2 = H1 + Q - L

381 = 268 + 34 - L

L = 268 + 34 - 381 = -79 kW

This is the work from the point of view of the air, that's why it is negative.

From the point of view of the machine it is positive.

4 0
4 years ago
The 40-ft-long A-36 steel rails on a train track are laid with a small gap between them to allow for thermal expansion. Determin
vfiekz [6]

Answer:

Ф = 0.02838 ft

F  = 1,032 N

Explanation:

To find out gap delta,

As it is case of free thermal expansion,

First we start with, some assumptions we have to made to solve this problem.

1. Thermal Expansion Coefficient of Steel is ∝= 6.45 ×10^(-6)

2. Modulas of elasticity for A-36 steel is E= 200 GPa

3. Area of rail is assumed to be unit area.

The gape required can be given by,

Ф = ∝  × ΔT  × L  ... where Ф= Gap Delta in ft

                                          ΔT= Temperature rise in F

                                               = 90- (-20)

                                               =  110 F

Ф =  6.45 ×10^(-6) × 110 × 40

Ф =  28,380 × 10^(-6) ft

Ф = 0.02838 ft     .... total gape required for expansion of steel rails

Stress induced in rails is given by,

   σ     =  ∝  × ΔT  × E

          =  6.45 ×10^(-6)   × 110  × 200

  σ      =  1,41,900 Pa

Now, let's find axial force in rails,

Here,we have to consider  ΔT= 20 F.

As due to temperature change, axial force generated in rails can be find by,

F = A × ∝ × ΔT× E × L

F = 1 × 6.45 × 10^(-6) × 20 × 200 × 10^(-9) × 40

F = 25,800 × 40 × 10^(-3)

F = 10,32,000 × 10^(-3)

F= 1,032 N

Finally, due to temperature change, rail is subjected to axial force, axial stress.

8 0
3 years ago
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