What is the molar mass of caso4?

Chemistry

2 answers:

Alexxx [7]3 years ago

6 0

Answer:

136.15 g/mol is the molar mass of calcium sulfate.

Explanation:

Molar mass is defined as a total sum of atomic masses of all and each type of atoms constituting the molecule.

Atomic mass of calcium = 40.08 g/mol

Atomic mass of sulfur = 32.07 g/mol

Atomic mass of oxygen = 16.00 g/mol

Molar mass of calcium sulfate, ( $CaSO_4$ ) :

$=1\times 40.08 g/mol+1\times 32.07 g/mol+4\times 16.00g/mol$

$=136.15 g/mol$

136.15 g/mol is the molar mass of calcium sulfate.

Vlada [557]3 years ago

5 0

136.14 g/mol is the molar mass

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2 years ago

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If 2.0 g of copper(II) chloride react with excess sodium nitrate, what mass of sodium chloride is formed in this double replacem

cluponka [151]

Taking into account the reaction stoichiometry, 1.729 grams of NaCl is formed.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

CuCl₂ + 2 NaNO₃ → Cu(NO₃)₂ + 2 NaCl

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

CuCl₂: 1 mole
NaNO₃: 2 moles
Cu(NO₃)₂ : 1 mole
NaCl: 2 moles

The molar mass of the compounds is:

CuCl₂: 134.44 g/mole
NaNO₃: 85 g/mole
Cu(NO₃)₂ : 187.54 g/mole
NaCl: 58.45 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

CuCl₂: 1 mole ×134.44 g/mole= 134.44 grams
NaNO₃: 2 moles ×85 g/mole= 170 grams
Cu(NO₃)₂ : 1 mole ×187.54 g/mole= 187.54 grams
NaCl: 2 moles ×58.45 g/mole= 116.9 grams

<h3>Mass of NaCl formed</h3>

The following rule of three can be applied: If by stoichiometry of the reaction 134.44 grams of CuCl₂ form 116.9 grams of NaCl, 2 grams of CuCl₂ form how much mass of NaCl?

$mass of NaCl=\frac{2 grams of CuCl_{2}x116.9 grams of NaCl }{134.44grams of CuCl_{2}}$