Answer is: specific gravity of glucose is 1,02.
d(glucose) = 1,02 g/ml.
d(water) = 1,00 g/ml.
Specific gravity of glucose = density of glucose ÷ density of water.
Specific gravity of glucose = 1,02 g/ml ÷ 1,00 g/ml.
Specific gravity of glucose = 1,02.
Specific gravity<span> is the ratio of the </span>density<span> of a substance (in this case glucose) to the density of a reference substance (water).</span>
I'm pretty sure its graph 4
V= 50. L n=45 mol T= 200°C = 473k P=?
CP)X 50.L)= (45 mol)(0.0821 light_kimol)(473k)
P = 30am or 4000 kPa
Answer:
10.81, Boron
Explanation:
I love the explanation Khan Academy gives.