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3 years ago

Is there a definite end to our atmosphere?

1 answer:

7 0

There is no definite end to earths atmosphere, but technically the border between the outer space and earth gets thinner as you move up from the earths surface. The Karman line is the closest definition there is which describes the end of the earth's atmosphere, it is 100 km above earth's sea level at approximately 1.56 % of total earth's radius. This describes the boundary between the outer space and the atmosphere.

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Atomic physicists usually ignore the effect of gravity within an atom. To see why, we may calculate and compare the magnitude of

STatiana [176]

Answer:

$2.27\cdot 10^{49}$

Explanation:

The gravitational force between the proton and the electron is given by

$F_G=G\frac{m_p m_e}{r^2}$

where

G is the gravitational constant

$m_p$ is the proton mass

$m_e$ is the electron mass

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_G=(6.67259\cdot 10^{-11} m^3 kg s^{-2})\frac{(1.67262\cdot 10^{-27}kg) (9.10939\cdot 10^{-31}kg)}{(3 m)^2}=1.13\cdot 10^{-68}N$

The electrical force between the proton and the electron is given by

$F_E=k\frac{q_p q_e}{r^2}$

where

k is the Coulomb constant

$q_p = q_e = q$ is the elementary charge (charge of the proton and of the electron)

r = 3 m is the distance between the proton and the electron

Substituting numbers into the equation,

$F_E=(8.98755\cdot 10^9 Nm^2 C^{-2})\frac{(1.602\cdot 10^{-19}C)^2}{(3 m)^2}=2.56\cdot 10^{-19}N$

So, the ratio of the electrical force to the gravitational force is

$\frac{F_E}{F_G}=\frac{2.56\cdot 10^{-19} N}{1.13\cdot 10^{-68}N}=2.27\cdot 10^{49}$

So, we see that the electrical force is much larger than the gravitational force.

5 0

3 years ago

Someone please help

saul85 [17]

Based on the attached image:

The name of the longitude line that passes through point A is the International Date Line
The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
Longitude 120° is B
Solar time at Point B is 4 pm
The location will correspond to any point on the same latitude as A

<h3>What are lines of longitude?</h3>

Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.

Longitude lines divide the earth into semi-circles.

Longitude lines are known as meridians and each meridian measures one arc degree of longitude.

Considering the attached image:

The name of the longitude line that passes through point A is the International Date Line
The longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.
The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° E
Longitude 120° is B
Solar time at Point B is 4 pm
the location will correspond to any point on the same latitude as A

In conclusion, longitude lines are imaginary lines and run from North to South on the earth.

Learn more about lines of longitude at: brainly.com/question/1939015

#SPJ1

8 0

1 year ago

A 25 N force stretches a spring 280 cm. What was the spring constant?

boyakko [2]

Answer:

F= 25N
∆l=280cm
K=?
you apply the formula = K:F/∆l
= 0,089N/cm

4 0

2 years ago

Read 2 more answers

3 An un calibrated mercury in glass thermometer immersed in melting ice. The length of the mercury thread is 25 mm when the ther

sammy [17]

Answer:

25 mm = 0 deg C

200 mm = 100 deg C

200 - 25 = 175 = change in thread per 100 deg C

95 - 25 = 70 mm - change in thread from 0 deg C

70 / 175 * 100 = 40 deg C final temperature at 95 mm

5 0

3 years ago

Your mass in kilograms if you weight 170 pounds

Aleonysh [2.5K]

1 pound ≈ 0.4536 kg

170 pounds ≈ 170 * 0.4536 kg

≈ 77.112 kg

5 0

3 years ago