The correct answer is c) 28 m/s.
Let's find the step-by-step solution. The motion of the monkey is an uniformly accelerated motion, with acceleration equal to

. The initial velocity of the monkey is zero, while the distance covered is S=40 m. Therefore, we can use the following relationship to find vf, the final velocity of the monkey:

from which
The magnitude of emf induced in the single coil of wire rotated in the uniform magnetic field is 0.171 V.
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Induced emf</h3>
The emf induced in the loop is determined by applying Faraday's law of electromagnetic induction.
emf = N(dФ/dt)
where;
- N is number of turns of the wire
- Ф is magnetic flux
Ф = BA
where;
- B is magnetic field strength
- A is the area of the loop
emf = NBA/t
A = πr²
A = π x (0.13)²
A = 0.053 m²
emf = NBA/t
emf = (1 x 3.746 x 0.053)/(1.16)
emf = 0.171 V
Thus, the magnitude of emf induced in the single coil of wire is 0.171 V.
Learn more about induced emf here: brainly.com/question/13744192
Answer:
power = 23.2 mW
Explanation:
given data
resister r = 5.80 kΩ
current measures I1 = 3.10 m A
measure current I2 = 1.10mA
solution
we get here I total
I = current 1 - current 2
I = 3.10 - 1.10
I = 2 mA
so here power will be
power = I²×R .............1
power = 2² × 5.80
power = 23.2 mW
The si unit of force is newton.
so, F is eqal to m*g