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4 years ago

11

What color does a red and blue jacket look through a green filter put over a red filter

1 answer:

pickupchik [31]4 years ago

8 0

Answer: black

Explanation:

A colour filter is a filter that lets only one colour pass through it. For example, a red filter lets only red colour pass through it, while a green filter lets only green light pass through it.

In this example, we have a red and blue jacket. At first, we put a red filter: this filter lets pass throuhg only the red light. Then, we put a green filter: this filter lets pass only green light through it. However, there is no green light coming from the previous filter (since only red light passes through it), so the jacket appears black (no colours).

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An average person can reach a maximum height of about 60 cm when jumping straight up from a crouched position. During the jump i

Iteru [2.4K]

Answer:

Explanation:

Height attained by body = 50 cm

= .5 m

Initial velocity = u

v² = u² - 2gh

0 = u² - 2gh

u² = 2 x 9.8 x .5

u = 3.13 m /s

During the initial period , the muscle stretches by around 10 cm during which force by ground reacts on the body and gives acceleration to achieve velocity of 3.13 m/s from zero .

v² = u² + 2as

3.13² = 0 + 2 a x .10

a = 49 m/s²

reaction by ground R

Net force

R-mg = ma

R= m ( g +a )

= mg + ma

=W + (W/g) x a

W ( 1 + a / g )

= W ( 1 + 49 / 9.8 )

= 6W

4 0

4 years ago

Plss help quick!!! Which component of the galaxy is the arrow pointing to?

uranmaximum [27]

I think it’s dust sorry if it wrong

7 0

3 years ago

A water-skier is moving at a speed of 14.3 m/s. When she skis in the same direction as a traveling wave, she springs upward ever

kiruha [24]

Answer:

a) 1.95 m/s

b) 5.56 m

Explanation:

Given that:

Velocity of the skier $(V_s)$ = 14.3 m/s

For the skier moving in the direction of the wave, we have:

Period (T) = 0.450 s

Relative velocity (V) of the skier in regard with the wave = $(V_s - V_w)$

where:

$V_s$ = velocity of the skier

$V_w$ = velocity of the wave

The wavelength $(\lambda)$ can be written as:

$\lambda = (V_s-V_w)T$

$\lambda = (V_s-V_w) 0.450m$ ---------------> Equation (1)

For the skier moving opposite in the direction of the wave, we have:

Period (T) = 0.342 s

Relative velocity (V) of the skier in regard with the wave = $(V_s + V_w)$

The wavelength $(\lambda)$ can be written as:

$\lambda = (V_s+V_w)T$

$\lambda = (V_s+V_w) 0.342m$ ------------------> Equation 2

Equating equation (1) and equation (2) and substituting $V_s$ = 14.3 m/s ; we have:

$(V_s-V_w) 0.450m = (V_s-V_w) 0.342m$

$0.450m(V_s)-0.450m(V_w) = 0.342m(V_s)+0.342m(V_w)$

Collecting the like terms; we have:

$0.450m(V_s) - 0.342m(V_s) = 0.342m(V_w)+0.450m(V_w)$

$(V_s)(0.450m - 0.342m) = (V_w)0.342m+0.450m$

$14.3m/s(0.450m - 0.342m) = (V_w)0.342m+0.450m$

$14.3m/s(0.108m = (V_w)0.792m$

$1.5444m^2/s = (V_w)0.792m$

$(V_w) = \frac{1.5444m^2/s}{ 0.792m}$

$(V_w) = 1.95 m/s$

b)

The Wavelength of the wave can be calculated using : $( \lambda }) = (V_s-V_w) 0.450m$

$({\lambda}) = (14.3 m/s -1.95 m/s)(0.450)$

$(\lambda) = (12.35)0.450m$

$(\lambda)= 5.5575 m$

λ ≅ 5.56 m

5 0

3 years ago

A force of 80 N is exerted on an object on a frictionless surface for a distance of 4 meters. If the object has a mass of 10 kg,

xxTIMURxx [149]

Answer:we can calculate the answer by following steps;

Explanation:

3 0

3 years ago

A sound wave is an example of an electromagnetic wave in nature. true or false?

Natasha2012 [34]

False. A sound wave is an example of a mechanical wave, not an EM wave.

Hope this helps! :)

5 0

4 years ago

Read 2 more answers