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3 years ago

For which scientific method do you use experimental and control groups?

Physics

2 answers:

Marrrta [24]3 years ago

4 0

Answer:

Analyzing data B.

Explanation:

laiz [17]3 years ago

3 0

Answer:

Explanation:

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Un automóvil acelera de 0 a 140 km/h en 9.8 segundos, determina su aceleración

guajiro [1.7K]

Answer:

The acceleration is 14.28 km/h^2

Explanation:

Step one:

Given data

initial speed u= 0 km/h

final speed v= 140km/h

time t= 9.8 seconds

Required

The acceleration of the car

Step two:

From a= v-u/t

substitute

a= 140-0/9.8

a=140/9.8

a=14.28 km/h^2

6 0

3 years ago

ANSWER ASAP PLS Finn drew a diagram to compare Einstein’s two postulates of relativity. A venn diagram with 2 intersecting circl

jarptica [38.1K]

Answer:

answer is option d

Explanation:

just took unit test edg 2021

9 0

3 years ago

Read 2 more answers

What is happening to the water molecules as it changes from ice to liquid water? *

g100num [7]

Answer:

They are gaining energy, can move and slide past each other.

Explanation:

Because as ice melts, the molocules gain energy/heat which warm them up and are able to slide/move apart from each other.

7 0

3 years ago

An aluminum wire is held between two clamps under zero tension at room temperature. Reducing the temperature, which results in a

Blababa [14]

Answer:

$\frac{\Delta L}{L} =5.37\times 10^{-4}$

Explanation:

Given:

cross sectional area of the wire, $A=5.75\times 10^{-6}\ m^2$

density of aluminium wire, $\rho=2.7\times 10^3\ kg.m^{-3}$

young's modulus of the material, $E=7\times 10^{10}\ N.m^{-2}$

wave speed, $v=118\ m.s^{-1}$

<u>We have mathematical expression for strain as:</u>

$\frac{\Delta L}{L} =\frac{\sigma}{E}$ ...............................(1)

and since, $\sigma =\frac{T}{A}$

where, T = tension force in the wire

equation (1) becomes:

$\frac{\Delta L}{L} =\frac{T}{A.E}$ ............................(2)

<u>Also velocity ofwave in tensed wire:</u>

$v=\sqrt{\frac{T}{\mu} }$ ...................................(3)

where: $\mu=$ linear mass density of the wire

$\therefore \mu=\rho \times A$

Now, equation (3) becomes

$v=\sqrt{\frac{T}{\rho \times A} }$

$T=v^2.\rho \times A$ ............................(4)

Using eq. (2) & (4) for tension T

$v^2.\rho \times A=A.E\times \frac{\Delta L}{L}$

$\frac{\Delta L}{L} =\frac{v^2.\rho}{E}$

putting the respective values

$\frac{\Delta L}{L} =\frac{118^2\times 2.7\times 10^3}{7\times 10^{10}}$

$\frac{\Delta L}{L} =5.37\times 10^{-4}$

6 0

3 years ago

An experimentalist fires a beam of electrons, creating a visible path in the air that can be measured. The beam is fired along a

gtnhenbr [62]

Answer:

Velocity of the electron in the beam.

Radius of the circulating electrons due to the magnetic field.

Explanation:

We have a Mathematical expression for the force on a moving charge in a magnetic field as:

$F=q.v.B.sin \theta$ ...........................(1)

where:

q= charge on the particle in coulomb

v= velocity of the charge projected into the magnetic field

B= intensity of the magnetic field in tesla

$\theta$ = angle between the velocity and direction of magnetic field

For the forces on rotating mass we have the formula:

$F=m.\frac{v^2}{r}$ ..........................................(2)

where:

m= mass of the charged particle

v= velocity of projection of charge into the magnetic field

r= radius of the path traced by the charge in the magnetic field

From eq. (1) and (2) we can calculate the magnetic field .

Now,

Using Ampere's Law we have:

$B = \frac{\mu_0 .I}{2 \pi r}$

where:

I= current in the wire

$\mu_0=$ The permeability of free space.

r= radial distance from the current carrying wire( in this case it is same as the radius of the circular path)

4 0

3 years ago