5.0 L vessel holds 3.0 mol n2, 2.0 mol f2, and 1.0 mol h2 at 273 K. What is the partial pressure of fluorine?
1 answer:
Answer:- 8.97 atm.
Solution:- Moles of each gas, volume of the vessel and temperature are given. So, we could easily use the partial pressure of each gas using ideal gas law equation.
PV = nRT
P is the pressure, V is the volume, n is the moles of the gas, R is universal gas constant and T is kelvin temperature.
The equation is rearranged for the pressure as:
To calculate the partial pressure of fluorine we will use its moles.
n = 2.0 mol
V = 5.0 L
T = 273 K
R = 0.0821
P = ?
Let's plug in the values and calculate the partial pressure of fluorine.
P = 8.97 atm
So, the partial pressure of fluorine gas is 8.97 atm.
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Therefore:
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Pi Bonds = 3
Explanation:
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