Answer:
Rate of formation of SO₃
= 7.28 x 10⁻³ M/s
Explanation:
According to equation 2 SO₂(g) + O₂(g) → 2 SO₃(g)
Rate of disappearance of reactants = rate of appearance of products
⇒
-----------------------------(1)
Given that the rate of disappearance of oxygen =
= 3.64 x 10⁻³ M/s
So the rate of formation of SO₃
= ?
from equation (1) we can write
![\frac{d[SO_{3}] }{dt} = 2 [-\frac{d[O_{2}] }{dt} ]](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5BSO_%7B3%7D%5D%20%7D%7Bdt%7D%20%3D%202%20%5B-%5Cfrac%7Bd%5BO_%7B2%7D%5D%20%7D%7Bdt%7D%20%5D)
⇒
= 2 x 3.64 x 10⁻³ M/s
⇒
= 7.28 x 10⁻³ M/s
∴ So the rate of formation of SO₃
= 7.28 x 10⁻³ M/s
In order from the most likely to bind an oxygen to least likely;
3 bound o2, po2=100mmhg1 bound o2, po2=100mmhg3 bound o2, po2=40mmhg<span>1 bound o2, po2=40mmhg
</span>
Haemoglobin is more likely to bind oxygen if its other oxygen binding sites have already bound to an oxygen molecule. The higher the partial pressure of oxygen in the blood also makes it more likely that the hemoglobin will bind oxygen.
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What is most widely accepted today is the giant-impact theory. It the Moon formed during a collision between the Earth and another small planet, about the There may indeed be several objects in orbit around Earth.