Ask question

Ask question

All categories

1 year ago

15

Based on the graph, how would you describe the net forces acting on the moving

1 answer:

ladessa [460]1 year ago

3 0

Given the velocity-time graph of an object.

The slope of a velocity-time graph gives the acceleration acting on the object.

From the graph, we can see that the slope of the graph is zero. That is, the velocity of the object is constant and hence the net acceleration acting on the object is zero.

From Newton's second law, the net force acting on an object is given by the product of the mass of the object and its velocity. Therefore when the acceleration of the object is zero, the net force on the object is also zero.

Therefore the net force acting on the given object is zero. Hence, the correct answer is option A.

You might be interested in

If an object that weighs 20 N is lifted from the ground to a

Radda [10]

Answer:

false 20 n x 0.32 m = 6.4 J

3 0

4 years ago

A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh

Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 $rad/sec^2$

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius $r=\frac{d}{2}=\frac{1.63}{2}=0.815m$

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

$\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec$

(b) We know that linear speed is given by

$v=r\omega =0.815\times 8.362=6.815m/sec$

(c) We have given final angular velocity $\omega _f=675rev/min$

And $\omega _i=79.9rev/min$

Time t = 63 sec

Angular acceleration is given by $\alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2$

(d) Change in angle is given by

$\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev$

7 0

3 years ago

The rate of change of velocity or speed is known as acceleration. If a car increases it speed form 10 to 20m/s in 2 seconds, the

lisov135 [29]

Answer:

A) 5 m/s/s

Explanation:

<u>Given the following data;</u>

Initial velocity = 10m/s²

Final velocity = 20m/s²

Time, t = 2 seconds.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

$Acceleration, a = \frac{final \; velocity - initial \; velocity}{time}$

Substituting into the equation, we have;

$Acceleration, a = \frac{20 - 10}{2}$

$Acceleration, a = \frac{10}{2}$

<em>Acceleration, a = 5m/s²</em>

7 0

3 years ago

Density Questions

Katen [24]

Explanation:

let's take the volume of each first:

ice cream: 10×10×4=400cm^3

freezer: 40×40×20=32,000cm^3

now we just divide: 32000/400=80

5 0

3 years ago

What kinds of bonds can happen between the elements of a compound

Anit [1.1K]

What kinds of bonds can happen between the elements of a compound?

<span>Covalent and Ionic</span>

4 0

3 years ago