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zhenek [66]
3 years ago
13

1. It takes 120 minutes for a man to ride his bicycle up the road to Alpe d'Huez in France. The vertical height of the climb is

1,120 m, and the combined mass of the rider and bicycle is 96 kg. What is the bicyclist's average power output, in W?
2. A steel cable with a total length of 100 m and a mass of 1000 kg is connected to two poles. The tension in the cable is 500 N, and the wind makes the cable vibrate with a frequency of 2 Hz. Calculate the wavelength of the resulting wave on the cable.
Physics
1 answer:
zloy xaker [14]3 years ago
3 0
To1. PE = mgh

PE potential energy
m mass
g 9.81
h height

P = PE / t

P power
t time


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I push a box with mass 10 kg across a 15 m room. If I apply a force of 20N to do this how much work is being done on the box?
devlian [24]
You could use the formula

W=Fd

F(force)=20N

D(distance/displacement) =15m

W=(20N)(15m)

W= 300 J
8 0
3 years ago
A paper airplane moving 2.33 m/s has 0.161 J of KE. What is its mass? (Unit = kg)
LekaFEV [45]

The kinetic energy of an object is given by:

KE = 0.5mv²

KE = kinetic energy, m = mass, v = speed

Given values:

KE = 0.161J, v = 2.33m/s

Plug in and solve for m:

0.161 = 0.5m(2.33)²

m = 0.059kg

4 0
3 years ago
3. What color of laser light shines through a diffraction grating with a line density of 500 lines/mm if the third maxima from t
mestny [16]

Answer:

Wavelength is 471 nm

Explanation:

Given that,

Lines per unit length of diffraction grating is 500 lines/mm.

The third maxima from the central maxima (m=3) is at an angle of 45°

We need to find the color of laser light shines through a diffraction grating.

The condition for maxima is :

d\sin\theta=m\lambda

d = 1/N, N = number of lines per mm

\lambda=\dfrac{1}{Nm}\sin\theta\\\\\lambda=\dfrac{10^{-3}}{500\times 3}\sin(45)\\\\\lambda=4.31\times 10^{-7}\\\\\text{or}\\\\\lambda=471\ nm

6 0
3 years ago
4.
zimovet [89]

Answer:

hindi ko gets

Explanation:

ang gulo naman nyan

8 0
2 years ago
Three Carnot engines operate between the following temperature limits.
Kipish [7]

Answer:c>a>b

Explanation:

Given

All the engine extracts same amount of heat(Q) from High-temperature reservoir

For a) 400 and 500 K

\eta _{engine}=1-\frac{T_L}{T_H}

\eta _{engine}=\frac{work\ supplied}{heat\ supplied}

1-\frac{400}{500}=\frac{W_a}{Q}

W_a=\frac{Q}{5}

For b)500 K and 600K

1-\frac{500}{600}=\frac{W_b}{Q}

W-b=\frac{Q}{6}

For c) 400 K and 600 K

1-\frac{400}{600}=\frac{W_c}{Q}

W_c=\frac{2Q}{3}

So c will give the highest amount of work

c>a>b

6 0
3 years ago
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