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4 years ago

11

Planet A and planet B are in circular orbits around a distant star.

1 answer:

evablogger [386]4 years ago

8 0

Answer:

$\frac{v_A}{v_B}=0.402$

Explanation:

The speed that planets must have in order for their orbit to be stable, is given by:

$v=\sqrt{\frac{GM}{r}}$

Here v It is called orbital speed, G is the gravitational constant, M is the mass of the star and r is the radius of the orbit. In this case we have:

$r_A=6.2r_B$

So, the ratio of their speed is:

$\frac{v_A}{v_B}=\frac{\sqrt{\frac{GM}{r_A}}}{\sqrt{\frac{GM}{r_B}}}\\\frac{v_A}{v_B}=\sqrt{\frac{r_B}{r_A}}\\\frac{v_A}{v_B}=\sqrt{\frac{r_B}{6.2r_B}}\\\frac{v_A}{v_B}=\sqrt{\frac{1}{6.2}}\\\frac{v_A}{v_B}=0.402$

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Explain how neurons convey information using both electrical and chemical signals.

8090 [49]

Answer:

Explanation:

Neurons communicate via both electrical signals and chemical signals. The electrical signals are action potentials, which transmit the information from one of a neuron to the other; the chemical signals are neurotransmitters, which transmit the information from one neuron to the next.

The electrical signal travels down the axon to the axon terminals where it tells the vesicles to release the neurotransmitters into the synaptic cleft which travel to the receptors of the receiving cell which releases the second messengers

6 0

3 years ago

A force of 10 N causes a spring to extend by 20 mm. Find: a) the spring constant of the spring in N/m

Mars2501 [29]

Answer:

formula used K=F/∆l

∆l is the elongation of the spring

F=10N
∆l=20mm===> 0.02m
K=10N divided 0.02m= 500N/m

6 0

3 years ago

The acceleration of gravity on earth is approximately 10 m/s2 (more precisely, 9.8 m/s2. if you drop a rock from a tall building

VLD [36.1K]

From the equation;
a= -1÷2gT2
a= -5×3(3)
a= -45m/s
it will drop about -45m/s2.

8 0

3 years ago

Find the de Broglie wavelength of the following. (a) a 4-MeV proton 14.3 Correct: Your answer is correct. fm (b) a 40-GeV electr

kherson [118]

a) de Broglie wavelength of a 4-MeV proton: 14.3 fm

b) de Broglie wavelength of a 40-GeV electron: 0.031 fm

Explanation:

a)

The de Broglie wavelength of an object is given by

$\lambda=\frac{h}{p}$ (1)

where

h is the Planck constant

p is the momentum of the particle

Here we want to find the de Broglie wavelength of a 4-MeV proton. The rest of mass of the proton in MeV is

$m_0 = 938 MeV$

And since $4MeV$ , this means that the proton is non-relativistic. So its kinetic energy is related to its momentum by

$E=\frac{p^2}{2m}$

which means

$p=\sqrt{2Em}$

where

$E=4 MeV \cdot 10^6 eV/MeV \cdot 1.6\cdot 10^{-19] J/eV=6.4\cdot 10^{-13} J$ is the kinetic energy

$m=1.67\cdot 10^{-27} kg$ is the proton mass

Substituting, we find

$\lambda=\frac{h}{\sqrt{2Em}}=\frac{6.63\cdot 10^{-34}}{\sqrt{2(6.4\cdot 10^{-13})(1.67\cdot 10^{-27})}}=14.3\cdot 10^{-15} m = 14.3 fm$

b)

In this case, the electron has kinetic energy of 40 GeV, while the rest mass of an electron is

$m_0 = 0.511 MeV$

Since $40 GeV >> 0.511 MeV$ , the electron is ultra-relativistic: so we can rewrite its energy as

$E = pc$

The equation (1) can also be rewritten as

$\lambda = \frac{hc}{pc}$

where c is the speed of light. The quantity at the denominator is the energy, so

$\lambda=\frac{hc}{E}$

where:

$E=40 GeV = 40\cdot 10^9 eV \cdot (1.6\cdot 10^{-19})=6.4\cdot 10^{-9} J$ is the energy of the electron

And substituting, we find:

$\lambda=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{6.4\cdot 10^{-9}}=3.1 \cdot 10^{-17} m = 0.031 fm$

Learn more about de Broglie wavelength:

brainly.com/question/7047430

#LearnwithBrainly

4 0

3 years ago

What is a living organism? Give a few examples.

zhuklara [117]

Answer:

It's a individual form of life. Examples of this are bacterium , protists and fungus

7 0

3 years ago