Answer:
a) 24.692 m/s
b) 19.4 m
Explanation:
To calculate the velocity at the nozzle outflow (V2) we use the Bernoulli equation:
We know that the velocity above the oil surface (V1) and the pressure at the nozzle outflow (P2) are negligible, the height in the exit is zero (Z2) then:
a) The velocity (V2) is:
![V2=[(\frac{P1}{pg}+Z1)(2g)]^{1/2}](https://tex.z-dn.net/?f=V2%3D%5B%28%5Cfrac%7BP1%7D%7Bpg%7D%2BZ1%29%282g%29%5D%5E%7B1%2F2%7D)
Substituting the known values we can get the velocity at the out:
Atmospheric pressure= 101000 Pa
Oil density= 0.88x(Water density)=0.88(1000kg/m3)=880kg/m3
![V2=[(\frac{150000Pa+101000 Pa}{(880 kg/m3)(9.81m/s)}+2m)(2(9.81m/s2))]^{1/2}](https://tex.z-dn.net/?f=V2%3D%5B%28%5Cfrac%7B150000Pa%2B101000%20Pa%7D%7B%28880%20kg%2Fm3%29%289.81m%2Fs%29%7D%2B2m%29%282%289.81m%2Fs2%29%29%5D%5E%7B1%2F2%7D)
b) To calculate the height we have to apply the Bernoulli equation between the outflow and the maximum height (Z3), so:
We know that the velocity above the stream (V3) and the pressure at the nozzle outflow (P2) are negligible, the pressure at the top of the stream (P3) is the atmospheric pressure, then:
Substituting the known values, the height (Z3) is:
Z3=Maximum Height=19.376=19.4 m
Answer:
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Explanation:
This scenario can be represented by an arithmetic progression AP.
nth term = a + nd
Where a is the first term given as 2.63 ft.
d is the common difference and is given as 5.3ft.
n is the particular second/time.
To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.
d = nth sum = (n/2)(2a+(n-1)d)
Where n = 10 seconds
a = 2.65 ft
d = 5.3 ft
Substituting the values we have;
d = (10/2)(2×2.65 + (10-1)5.3)
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Answer:
7: C 8:All of These
Explanation:
Im almost 100% sure on both of these. Feedback is like critism and you'll get nowhere focusing on all good and no bad. You can't go to the doctor on your own if you're a child for technically it's both yours and your parents. Your teacher is responsible for notifying your parents and you are responsible for telling your teacher.
Athletes of any kind can use technology to monitor things like their BMI (body mass index) or weight or anything of the sort to target what they need to work on to improve their health.
Answer: The lac Y and lac Z genes are turned off when lactose is present. Is a false statement about E coli and the lac operon. Therefore the correct option is A.
Explanation:
Escherichia coli is an enteric bacteria that makes use of lactose operon (or lac operon) for its lactose metabolism. The lac operon is made up of three genes which includes lacZ, lacY and Lac A. These genes are expressed only when lactose is present and glucose is absent. Also the lac repressor acts as a lactose sensor while the catabolite activation protein (CAP) acts as a glucose sensor. They help in turning on and off the genes with respect to lactose and glucose levels.
The lac Y and lac Z genes are turned off (not expressed) when glucose is present and lactose absent, but are expressed when glucose is absent and lactose present. Therefore option A is a false statement.
