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saul85 [17]
3 years ago
9

How do natural actions such as weathering, erosion, and soil formation affect Earth's surface?

Physics
1 answer:
zimovet [89]3 years ago
8 0
There are plates under the surface that shift when there is interruption on the surface <span />
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From Earth to the center of our galaxy is about 300,000 light years, meaning that light coming from a star in the center of our
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<span>it takes about about 37,200 years for light to travel 1 light year. So the answer would have to be false. It would take way longer than 300k years

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A student measures the speed of sound by echo destiny classes hands and then measures the time to hear the echo his distance to
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Explanation:

∆x=300 m×2

∆t=1.5 s

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Which part of the electromagnetic spectrum have the highest level of photon energy
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The energy carried by one photon is directly proportional to its
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3 years ago
The tension in the horizontal towrope pulling a water-skier is 250 N while the skier moves due west a distance of 50 m. How much
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A long thin uniform rod of length 1.50 m is to be suspended from a frictionless pivot located at some point along the rod so tha
Dvinal [7]

Answer:

0.087 m

Explanation:

Length of the rod, L = 1.5 m

Let the mass of the rod is m and d is the distance between the pivot point and the centre of mass.

time period, T = 3  s

the formula for the time period of the pendulum is given by

T = 2\pi \sqrt{\frac{I}{mgd}}    .... (1)

where, I is the moment of inertia of the rod about the pivot point and g is the acceleration due to gravity.

Moment of inertia of the rod about the centre of mass, Ic = mL²/12

By using the parallel axis theorem, the moment of inertia of the rod about the pivot is

I = Ic + md²

I = \frac{mL^{2}}{12}+ md^{2}

Substituting the values in equation (1)

3 = 2 \pi \sqrt{\frac{\frac{mL^{2}}{12}+ md^{2}}{mgd}}

9=4\pi^{2}\times \left ( \frac{\frac{L^{2}}{12}+d^{2}}{gd} \right )

12d² -26.84 d + 2.25 =  0

d=\frac{26.84\pm \sqrt{26.84^{2}-4\times 12\times 2.25}}{24}

d=\frac{26.84\pm 24.75}{24}

d = 2.15 m , 0.087 m

d cannot be more than L/2, so the value of d is 0.087 m.

Thus, the distance between the pivot and the centre of mass of the rod is 0.087 m.

3 0
3 years ago
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