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saul85 [17]
3 years ago
9

How do natural actions such as weathering, erosion, and soil formation affect Earth's surface?

Physics
1 answer:
zimovet [89]3 years ago
8 0
There are plates under the surface that shift when there is interruption on the surface <span />
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A 68 kg object, starting from rest, travels from point A to point B at a rate of 30 m/s in 2 hours. What is the applied force on
Natasha2012 [34]

Answer:

\huge\boxed{\sf F = 0.28\ N}

Explanation:

<h3>Given Data:</h3>

Mass = m = 68 kg

Velocity = v = 30 m/s

Time = 2 hours = 2 × 60 × 60 = 7200 s

<h3>Required:</h3>

Force = F = ?

<h3>Formula to be used:</h3>

\displaystyle F = \frac{mv}{t}

<h3>Solution:</h3>

\displaystyle F = \frac{(68)(30)}{7200} \\\\F = \frac{2040}{7200} \\\\F = 0.28 N\\\\\rule[225]{225}{2}

7 0
1 year ago
a man pushes on a wall with a force of 50N. what are the size and direction of the force that the wall exert on the man?
Ira Lisetskai [31]
According to Newton's 3rd law of motion, every action has an equal and opposite reaction. So Wall must apply a force of 50 Newton but in opposite direction. Hope you got it :-D
5 0
3 years ago
What is a benefit of increased physical fitness
8_murik_8 [283]
The benefit's of increased physical fitness is better health, more pleasing appearance to some, stronger muscles and the reduction of fat.
5 0
3 years ago
wo parallel conducting plates are separated by 10.0 cm, and one of them is taken to be at zero volts. (a) What is the magnitude
melisa1 [442]

Answer:

<em> -18896.49 V/m</em>

<em></em>

Explanation:

Distance between the two plates = 10 cm = 10 x 10^{-2} m = 0.1 m

Also, one of the plates is taken as<em> zero volt.</em>

a. The potential strength between the zero volt plate, and 7.05 cm (0.0705 m) away is 393 V

b. The potential strength between the other plate, and 2.95 cm (0.0295 m) away is 393 V

<em>Potential field strength = -dV/dx</em>

where dV is voltage difference between these points,

dx is the difference in distance between these points

For the first case above,

potential field strength = -393/0.0705 = -5574.46 V/m

For the second case ,

potential field strength = -393/0.0295 = -13322.03 V/m

Magnitude of the field strength across the plates will be

-5574.46 + (-13322.03) = -5574.46 + 13322.03 =<em> -18896.49 V/m</em>

6 0
3 years ago
you arrive at an intersection with traffic lights that arent working because of a power outage .what do you do
ElenaW [278]
Use it as a four way stop.
6 0
3 years ago
Read 2 more answers
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