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3 years ago

Which of these particles is classified as a lepton?

Physics

2 answers:

netineya [11]3 years ago

6 0

(a)-electron, create a negative solution

sashaice [31]3 years ago

4 0

Answer:

(A)-electron

Explanation:

Particles can be classified into:

- Leptons: particles which do not feel the strong interaction

- Hadrons: particles which interact by strong nuclear forces (they are actually not fundamental particles, since they are composed of quarks)

- Boson: the mediators of the four fundamental forces

The given options in this problem are:

(A)-electron --> LEPTON (because it does not feel the strong interaction)

(B)-proton --> HADRON (it consists of quarks)

(C)-neutron --> HADRON (it consists of quarks)

(D)-photon --> BOSON (it is the mediator of the electromagnetic force)

(E)-boson --> BOSON

So, the only lepton among the choices is (A) electron.

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How does the state of matter of the medium through which the sound waves and light waves travel theough affect their velocity

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Answer:

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Explanation:

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3 years ago

Summarize how the components of health are related to wellness.

skelet666 [1.2K]

Answer:

there are 5 main aspects of personal health: physical, emotional,social,spiritual, and intellectual.

physical weelness indicates a high levelnof endurance, flexibility and strength. it incorporates daily exercise through cardiovascular and muscular activities.

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4 0

3 years ago

Read 2 more answers

while you are waiting to begin a foot race , you can feel your heart rate go up . This is the _ at work.

Ymorist [56]

Answer:

Sympathetic nervous system.

Explanation:

The sympathetic nervous system prepares the body for the “fight or flight” response during any potential danger. The sympathetic nervous system (SNS) increases heart rate. A faster heart rate (usually) pumps more oxygen-rich blood to the brain and lungs. This can give you the energy to run.

While you are waiting to begin a foot race, you can feel your heart race go up. This is the sympathetic nervous system at work.

7 0

3 years ago

At some instant and location the electric field associated with an electromagnetic wave in vacuum has the strength 96.5 V/m. Fin

prisoha [69]

Answer:

B = 32.17 x 10^-8 Tesla

u = 8.24 x 10^-8 J/m^3

P/A = 24.72 W/m^2

Explanation:

E = 96.5 V/m

velocity of light, c = 3 x 10^8 m/s

Let B be the magnetic field.

The relation between the electric field strength and the magnetic field strength is given by

B = E / c = 96.5 / (3 x 10^8) = 32.17 x 10^-8 Tesla

Let u be the energy density.

$u = \frac{1}{2}\times \varepsilon _{0}E^{2}+\frac{1}{2\mu _{0}}B^{2}$

$u = \frac{1}{2}\times 8.854\times 10^{-12}\times 96.5\times 96.5+\frac{1}{2\times 4\times 3.14\times 10^{-7}}\times 32.17^{2}\times 10^{-16}$

u = 8.24 x 10^-8 J/m^3

Let Power flow per unit area is

P/A = u x c = 8.24 x 10^-8 x 3 x 10^8 = 24.72 W/m^2

7 0

3 years ago

A force of 30 N is applied tangentially to the rim of a solid disk of radius 0.10 m. The disk rotates about an axis through its

den301095 [7]

Answer:

m = 4.0 Kg

Explanation:

Using an analogy with the Newton's 2nd law for point masses, for rigid bodies, the external net torque on a rigid body, is equal to its rotational inertia (I), times the angular acceleration (α) of the body, as follows:

$\tau_{ext} = I* \alpha (1)$

Since the magnitude of the torque is the product of the value of the force times the perpendicular distance between the line of action of the force and the axis of rotation, and the force is tangential to the rim of the disk, we can write the following expression:

$\tau = F*r*sin 90 = F*r (2)$

For a solid disk, the rotational inertia regarding an axis through its center, and perpendicular to its face is as follows:

$I = \frac{m*r^{2}}{2} (3)$

Replacing (3) in (1), and (2) in the left side of (1) also, we can solve for m, as follows:

$m = \frac{2*30.0N}{0.1m*150(1/s2)} = 4.0 Kg (4)$

So, the mass of the disk is 4.0 Kg.

7 0

3 years ago