Newton's second law of motion<span> can be formally stated as follows: The acceleration of an object as produced by a net </span>force<span> is directly proportional to the magnitude of the net </span>force, in the same direction as the netforce<span>, and inversely proportional to the mass of the object</span>
Complete Question
A voltaic cell is constructed with two 
electrodes. The two cell compartment have ![[Zn^{2+}] = 1.6 \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%20%3D%20%201.6%20%5C%20M)
and ![[Zn^{2+}] = 2.00*10^{-2} \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D%20%3D%20%202.00%2A10%5E%7B-2%7D%20%5C%20%20M)
respectively.
What is the cell emf for the concentrations given? Express your answer using two significant figures
Answer:
The value is 
Explanation:
Generally from the question we are told that
The concentration of ![[Zn^{2+}]](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D)
at the cathode is ![[Zn^{2+}]_a = 1.6 \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D_a%20%3D%20%201.6%20%5C%20M)
The concentration of at the anode is ![[Zn^{2+}]_c = 2.00*10^{-2} \ M](https://tex.z-dn.net/?f=%5BZn%5E%7B2%2B%7D%5D_c%20%3D%20%202.00%2A10%5E%7B-2%7D%20%5C%20%20M)
Generally the the cell emf for the concentration is mathematically represented as
![E = E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}](https://tex.z-dn.net/?f=E%20%3D%20%20E%5Eo%20-%20%5Cfrac%7B0.0591%7D%7B2%7D%20log%5Cfrac%7B%5BZn%5E%7B2%2B%7D%5Da%7D%7B%20%5BZn%5E%7B2%2B%7D%5Dc%7D)
Generally the 
is the standard emf of a cell, the value is 0 V
So
![E = 0 - \frac{0.0591}{2} * log[\frac{ 2.00*10^{-2}}{1.6} ]](https://tex.z-dn.net/?f=E%20%3D%20%200%20%20-%20%20%5Cfrac%7B0.0591%7D%7B2%7D%20%20%2A%20log%5B%5Cfrac%7B%202.00%2A10%5E%7B-2%7D%7D%7B1.6%7D%20%5D)
=>
I’m pretty sure it’s hertz
but if it’s wrong i apologize
Answer: Do you need help with how to get the photograph?
Explanation:It's in the comments if you want to known have a good day!
:)
Answer:
C. 100
D.3
E. 33.3
Explanation:
C. Mechanical Advantage=Load / Effort
= 200N
--------
100N
Therefore,. = 100
D. I. Velocity Ratio= distance moved by the effort / distance moved by load
= 30cm/10cm
= 3
II. Efficiency= M.A / V.R
= 100/3
= 33.33
