<h2>Ratio of free fall acceleration of Tokyo to Cambridge = 0.998</h2>
Explanation:
We know the equation

where l is length of pendulum, g is acceleration due to gravity and T is period.
Rearranging

Length of pendulum in Tokyo = 0.9923 m
Length of pendulum in Cambridge = 0.9941 m
Period of pendulum in Tokyo = Period of pendulum in Cambridge = 2s
We have

Ratio of free fall acceleration of Tokyo to Cambridge = 0.998
The relationship between the period of an oscillating spring and the attached mass determines the ratio of the period to
.
Response:
- The ratio of the period to
is always approximately<u> 2·π : 1</u>
<u />
<h3>How is the value of the ratio of the period to

calculated?</h3>
Given:
The relationship between the period, <em>T</em>, the spring constant <em>k</em>, and the
mass attached to the spring <em>m</em> is presented as follows;

Therefore, the fraction of of the period to
, is given as follows;

2·π ≈ 6.23
Therefore;

Which gives;
- The ratio of the period to
is always approximately<u> 2·π : 1</u>
Learn more about the oscillations in spring here:
brainly.com/question/14510622
<em>velocity over time I think</em>