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3 years ago

A toy car's movements is measured using photogates.

Physics

2 answers:

Sedbober [7]3 years ago

8 0

The answer is A

good luck in the future #BLM

Cloud [144]3 years ago

3 0

Answer:

a) the velocity increases then decreases.

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What is the main difference between work power and energy

liubo4ka [24]

Answer:

Work is the energy required to move an object from one point to another. while power is the energy transferred per unit time.

Energy can also be defined as the ability to do work.

6 0

2 years ago

A car, moving along a straight stretch of highway,

yarga [219]

<span>We know that an object in moving with acceleration follow the rule according that the distance covered will be : d = Vi*t + 1/2*a*t^2 where d is distance, Vi is initial speed, and a is acceleration Then after 1 km which is 1000 metres we have: 1000 = Vi *71.2 + 1/2*0.0499*(71.2)^2 Vi = (1000-1/2*0.0499*(71.2)^2)/71.2 = 1000/71.2 - 1/2*0.0499*71.2 = 12.27 m/s Then the car was going at 12.27 m/s when started to accelerate.</span>

5 0

3 years ago

How much energy in joules would be produced if the sun converts 8 kg of mass totally into energy? (hints: )?

Naddik [55]

Roughly 78.5 but more precise would be 78.4531

7 0

2 years ago

A uniform electric field of magnitude 442 N/C pointing in the positive x-direction acts on an electron, which is initially at re

Brums [2.3K]

A) The electric field is constant and in the same direction as the electron's displacement, so the work done is given by:

W = Fd

W = work, F = electric force, d = displacement

The electric force on the electron is given by:

F = Eq

F = electric force, q = electron charge

Substitute F:

W = Eqd

Given values:

E = 442N/C, q = 1.6×10⁻¹⁹C, d = 3.50×10⁻²m

Plug in and solve for W:

W = 442(1.6×10⁻¹⁹)(3.50×10⁻²)

W = 2.48×10⁻¹⁸J

B) The electric field does work to move the electron. Apply the conservation of energy and you'll see that the electron's potential energy loss is equal to the work done by the field in moving the electron.

The electric potential energy change is -2.48×10⁻¹⁸J

C) Apply the work-energy theorem; the electron's kinetic energy equals the work done on it by the field.

KE = 0.5mv² = W

m = electron mass, v = velocity, W = work

Given values:

W = 2.48×10⁻¹⁸J, m = 9.11×10⁻³¹

Plug in and solve for v:

0.5(9.11×10⁻³¹)v² = 2.48×10⁻¹⁸

v = 2.33×10⁶m/s

3 0

3 years ago

Charge Q1 = 6.0 nC is at (0.30 m, 0), charge Q2 = -1.0 nC is at (0, 0.10 m), and charge . What are the magnitude and direction o