We will have the following:
So, the heat to add is 3611.52 Joules.
4. A bullet of mass 30 g is fired from a rifle of mass 5kg at a speed of 259m/s.
1 answer:
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Answer:
sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j
Explanation:
We have given first vector which has length of 7 units and makes an angle of 30° with positive x-axis
So x component of the vector
y component of the vector
So vector will be 6.06i+3.5j
Now other vector of length of 7 units and makes an angle of 120° with positive x-axis
So x component of vector
y component of the vector
Now sum of these two vectors is 6.06i+3.5j-3.5i+6.06j = 2.56i+9.56j
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1) First of all, since we know the radius of the wire (
), we can calculate its cross-sectional area
2) Then, we can calculate the current density J inside the wire. Since we know the current,
, and the area calculated at the previous step, we have
3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity
of the aluminium, the electric field is given by
1) First of all, since we know the radius of the wire (
2) Then, we can calculate the current density J inside the wire. Since we know the current,
3) Finally, we can calculate the electric field E applied to the wire. Given the conductivity