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Blizzard [7]
3 years ago
10

When clouds form, what does water vapor turn into?

Physics
2 answers:
ra1l [238]3 years ago
7 0

Answer:

liquid water is your correct answer.

Explanation:

Jlenok [28]3 years ago
3 0

Answer:liquid water

Explanation:it turns into liquid water when it rains

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An isolated conductor has a net charge of +12.0 × 10- 6 c and a cavity with a particle of charge q = +3.70 × 10-6
pychu [463]
This is just a simple problem finding out the outer surface charge, the inner surface charge and the net charge. Net charge by definition means the difference between two charges. In this case, the formula that is applicable here is outer surface charge = total net charge - inner cavity surface charge. Since we are given already with the net charge equal to 12.0 x10-6 C and the inner charge magnituude f 3.7 x10-6 C, the the total charge must be outer charge is +10x10(-6)) - (-3.0x10(-6)) = +1.3x10(-5) C. 
Charges are measured in coloumbs and most likely exist on surfaces of entities like particles, walls etc.
8 0
2 years ago
This person does work to stretch the rubber band. When will the potential energy be the greatest?
antiseptic1488 [7]

the rubber band will be at its greatest when its fully stretched out

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3 years ago
Which object is least likely to allow light to pass through it?
jeka57 [31]

a tree truck

is the answer i hope this helps you xD


6 0
3 years ago
Read 2 more answers
A commuter airplane starts from an airport and takes theroute. The plane first flies to city A, located 175 km away in a directi
bearhunter [10]

Answer:

245.45km in a direction 21.45° west of north from city A

Explanation:

Let's place the origin of a coordinate system at city A.

The final position of the airplane is given by:

rf = ra + rb + rc    where ra, rb and rc are the vectors of the relative displacements the airplane has made. If we separate this equation into its x and y coordinates:

rfX = raX+ rbX + rcX = 175*cos(30)-150*sin(20)-190 = -89.75km

rfY = raY + rbY + rcT = 175*sin(30)+150*cos(20) = 228.45km

The module of this position is:

rf = \sqrt{rfX^2+rfY^2} = 245.45km

And the angle measure from the y-axis is:

\alpha =atan(rfX/rfY) = 21.45\°

So the answer is 245.45km in a direction 21.45° west of north from city A

6 0
3 years ago
Find the orbital speed v for a satellite in a circular orbit of radius R.Express the orbital speed in terms of G, M, and R.
AlekseyPX
<h2>Answer:V=\sqrt{G\frac{M}{R}}  </h2>

The velocity of a satellite describing a circular orbit is <u>constant</u> and defined by the following expression:

V=\sqrt{G\frac{M}{R}}     (1)

Where:

G is the gravity constant

M the mass of the massive body around which the satellite is orbiting

R the radius of the orbit (measured from the center of the planet to the satellite).

Note this orbital speed, as well as orbital period, does not depend on the mass of the satellite. I<u>t depends on the mass of the massive body.</u>

In addition, this orbital speed is constant because at all times <u>both the kinetic energy and the potential remain constant</u> in a circular (closed) orbit.

5 0
3 years ago
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