Question

In a certain region the average horizontal component of Earth's magnetic field is 22 μT, and the average inclination or "dip" is 75°. What is the corresponding magnitude of Earth's magnetic field in microteslas?

Answer 1

Answer:

B= 82.105 μT

Explanation:

Given that

Dip angle ,θ = 75°

Horizontal component of $B_h$ = 22 μT

The magnitude of earth magnetic filed given as

$B= B_h tan\theta$

Noe by putting values in the above equation we get

$B= 22\ \mu\ tan75^{\circ}$

B= 82.105 μT

Therefore magnetic filed in the microteslas will be 82.105 μT .