Answer:
c.if the flow is laminar it could become turbulent.
Explanation:
The Reynolds number (Re) is a dimensionless quantity used to help predict flow patterns in different fluid flow situations. At low Reynolds numbers of below 2300 flows tend to be dominated by laminar, while at high Reynolds numbers above 4000, turbulence results from differences in the fluid's speed and direction. In between these values is the transition region of flow.
In practice, fluid flow is generally chaotic, and very small changes to shape and surface roughness of bounding surfaces can result in very different flows.
Answer:
a. 33120MJ
b. 5.6
c. 48
Explanation:
∆U= 120,000 KJ/h
Since
1 day = 24 hrs
14 days =24 x 14 hrs
14 days = 336 hrs
∆U = 120000 x 336 KJ
=40320000KJ
K = 1000
M = 1000000
∆U = 403200 MJ
Work done
W= 2000 KW.h ( 1 h = 3600 s)
W= 7200 MJ
According to the first law of thermodynamics
∆U = Q+W
Q= 40320 - 7200 MJ
1)Qa=33120 MJ
Coefficient of performance
COP = ∆U/W
COP= 40320 / 7200
2)COP = 5.6
3)COP of ideal heat pump
Th/(Th - Tl)
Th = 15°C
Tl = 9°C
Convert Celsius to Kelvin
273 + 15 = 288
288/(15-9)
288/6
48
COP= 48
Answer:
E = 7333.33 mm
Explanation:
The annual evapotranspiration (E) amount can be calculated using the water budget equation:
(1)
<u>Where</u>:
<em>P: is the precipitation = 2500 mm, </em>
<em>Q(in): is the water flow into the river of the farmland = 5 m³/s, </em>
<em>ΔS: is the change in water storage = 2.5x10⁶ m³, </em>
<em>Q(out): is the water flow out of the river of the farmland = 4 m³/s.</em>
<em>Δt: is the time interval = 1 year = 3.15x10⁷ s </em>
<em>A: is the surface area of the farmland = 6.0x10⁶ m² </em>
Solving equation (1) for ET we have:


Therefore, the annual evapotranspiration amount is 7333.33 mm.
I hope it helps you!
The answer is D concept. For example, I grasp the concept of the idea.