Answer:
1. CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻
2. HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
3. H₂CO₃ → H₂O + CO₂
Basic solution
Explanation:
Brønsted Lowry theory:
Acid → Release a proton
Base → Accept a proton
1. CO₃⁻² + H₂O ⇄ HCO₃⁻ + OH⁻
Carbonate takes a proton from the water
2. HCO₃⁻ + H₂O ⇄ H₂CO₃ + OH⁻
Bicarbonate takesa proton from the water to produce carbonic acid.
3. H₂CO₃ → H₂O + CO₂
Carbonate acid decomposes into CO₂ and H₂O
In the first reaction, when the carbonate takes a proton from the water, water releases OH⁻, so the solution is basic.
Because on burning plastic produce toxic gases which is harmful for our earth
<h3>
Answer:</h3>
D. CH₃O₆
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Explanation:</h3>
- We are given the ratio of carbon, hydrogen and oxygen in a compound as 14: 42 : 84
We are supposed to determine the empirical formula of the compound;
- We need to know what is an empirical formula;
- An empirical formula of a compound is a formula that shows the simplest whole number ratio of elements in a compound.
In this case;
The ratio of C : H : O is 14 : 42 : 84
- Note, this is not the simplest ratio.
But we can simplify further to get the simplest whole number ratio;
- Therefore, 14 : 42 : 84 is equal to 1 : 3 : 6
- Thus, the simplest whole number ratio of C : H : O in the compound is 1 : 3 : 6
- Therefore, the empirical formula of the compound is CH₃O₆
41.38 % Mg
55.17 % O
3.45 % H
Explanation:
What is the percent composition of magnesium hydroxide Mg(OH)₂?
To find the percent composition we follow the next algorithm.
First we calculate the molar mass of Mg(OH)₂:
molar mass of Mg(OH)₂ = molar mass of Mg × 1 + molar mass of O × 2 + molar mass of H × 2
molar mass of Mg(OH)₂ = 24 × 1 + 16 × 2 + 1 × 2 = 58 g/mole
Now we devise the next reasoning:
if in 58 g of Mg(OH)₂ there are 24 g of Mg, 32 g of O and 2 g of H
then in 100 g of Mg(OH)₂ there are X g of Mg, Y g of O and Z g of H
X = (100 × 24) / 58 = 41.38 % Mg
X = (100 × 32) / 58 = 55.17 % O
X = (100 × 2) / 58 = 3.45 % H
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percent composition
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The number of molecules involved in the reaction, in this case, the number of Ag atoms involved.
