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adoni [48]
3 years ago
12

How many neutrons does element X have if its atomic number is 26 and its mass number is 82?

Physics
1 answer:
taurus [48]3 years ago
6 0

The mass number is calculated by adding the number of protons and the number of neutrons.

Therefore, you can find the number of neutrons by subtracting the number of protons from the mass number. The number of protons is equal to the atomic number, therefore you just have to do the mass number - atomic number to find the number of neutrons.

82 - 26 = 56 neutrons.

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What kind of stars make up the galactic nucleus?
Hatshy [7]
I think the correct answer would be old and metal poor stars are found in the galactic nucleus. This nucleus us a region in the center of a galaxy which contains a higher luminosity than other parts. It produces very high amounts of energy. Hope this helps.
4 0
3 years ago
Read 2 more answers
A block of mass 3.20 kg is placed against a horizontal spring of constant k = 865 N/m and pushed so the spring compresses by 0.0
Aliun [14]

Answer:

a) The initial elastic potential energy of the block-spring system is 28.113 joules.

b) The final speed of the block is approximately 4.192 meters per second.

Explanation:

a) By applying Hooke's law and definition of work, we define the elastic potential energy (U_{g}), measured in joules, by the following formula:

U_{g} = \frac{1}{2}\cdot k\cdot x^{2} (1)

Where:

k - Spring constant, measured in newtons per meter.

x - Deformation of the spring, measured in meters.

If we know that k = 865\,\frac{N}{m} and x = 0.065\,m, then the elastic potential energy is:

U_{g} = \frac{1}{2}\cdot \left(865\,\frac{N}{m} \right) \cdot (0.065\,m)

U_{g} = 28.113\,J

The initial elastic potential energy of the block-spring system is 28.113 joules.

b) According to the Principle of Energy Conservation, the initial elastic potential energy of the block-spring system becomes into translational kinetic energy, that is:

U_{g} = \frac{1}{2}\cdot m\cdot v^{2} (2)

Where:

m - Mass, measured in kilograms.

v - Final speed, measured in meters per second.

Then, the final speed is cleared:

v = \sqrt{\frac{2\cdot U_{g}}{m} }

If we know that U_{g} = 28.113\,J and m = 3.20\,kg, then the final speed of the block is:

v = \sqrt{\frac{2\cdot (28.113\,J)}{3.20\,kg} }

v \approx 4.192\,\frac{m}{s}

The final speed of the block is approximately 4.192 meters per second.

3 0
3 years ago
Two electrodes connected to a 9.0 v battery are charged to ±45 nc. What is the capacitance of the electrode?
mart [117]

Answer:

5\cdot 10^{-9} F

Explanation:

The capacitance of the electrode is given by:

C=\frac{Q}{V}

where

C is the capacitance

Q is the charge on the electrode

V is the potential difference

In this problem, we have

Q=45 nC=45\cdot 10^{-9} C

V = 9.0 V

Substituting into the equation, we find

C=\frac{45\cdot 10^{-9}C}{9.0 V}=5\cdot 10^{-9} F (5 nF)

6 0
3 years ago
Please select the word from the list that best fits the definition
Elenna [48]

Answer:

Hi... Your answer is impulse

8 0
3 years ago
A physical quantity X is connected from X = ab2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3
Hoochie [10]

Answer: 11%

Explanation:

Given that

X = ab^2/C. Calculate percentage error in X, when percentage error in a,b,c are 4,2 and 3 respectively.

Percentage error of b = 2%

Percentage error of b^2 = 2 × 2 = 4

When you are calculating for percentage error that involves multiplication and division, you will always add up the percentage error values.

Percentage error of X will be;

Percentage error of a + percentage error of b^2 + percentage error of c

Substitute for all these values

4 + 4 + 3 = 11%

Therefore, percentage error of X is 11%

3 0
3 years ago
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