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vlada-n [284]
3 years ago
15

A covalent bond is formed as the result of

Chemistry
2 answers:
agasfer [191]3 years ago
8 0

Answer: Sharing an electron pair

Explanation:

Covalent bonding is the sharing of electrons between two non metallic elements. Both elements in a covalent bond are completely in octet meaning their outer valence shell is full.

a_sh-v [17]3 years ago
7 0
B .sharing an electron pair
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Help! Locks at 12
marta [7]

Answer is #4 (neutrons)

Explanation:

Total mass before the reaction is 236 amu. The total mass of the two elements is 233 amu. This means that there are 3 amus carried by element X. Looking at the total atomic number of the two elements after reaction, it's 92, the same as the one at the beginning. This means that element X has zero atomic number, which could only be a neutron.

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How far he drove, in miles?
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The answer is C (xy)
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A 1.25 g sample of aluminum is reacted with 3.28 g of copper (II) sulfate. What is the limiting reactant? 2Al(s) + 3CuSO4(aq) →
vova2212 [387]

Answer:

Copper (II) sulfate

Explanation:

Given reaction is

2Al(s) + 3CuSO4(aq) → Al2(SO4)3(aq) + 3Cu(s)

Amount of aluminum = 1·25 g

Amount of copper (II) sulfate = 3·28 g

Atomic weight of Al = 26 g

Molecular weight of CuSO4 ≈ 159·5

Number of moles of Al = 1·25 ÷ 26 = 0·048

Number of moles of CuSO4 = 3·28 ÷ 159·5 = 0·021

From the above balanced chemical equation for every 2 moles of aluminum, 3 moles of copper (ll) sulfate will be required

So for 1 mole of Al, 1·5 moles of copper (ll) sulfate will be required

For 0·048 moles of Al, 1.5 × 0·048 moles of copper (ll) sulfate will be required

∴ Number of moles of copper (ll) sulfate required = 0·072

But we have only 0·021 moles of copper (ll) sulfate

As copper (ll) sulfate is not there in required amount, the limiting reactant will be copper (ll) sulfate

∴ The limiting reactant is copper (ll) sulfate

7 0
3 years ago
How many moles of AgNO3 must react to form 0. 854 mol Ag? mol AgNO3.
babunello [35]

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

The balanced chemical equation for the dissolution of silver nitrate has been:

\rm AgNO_3\;\rightarrow\;Ag^+\;+\;NO_3^-

The aqueous solution of silver nitrate has been dissociated into the constituent silver and nitrate ions.

In a balanced chemical equation, the coefficient has been equivalent to the moles of each reactant forming the moles of product.

From, the balanced equation,

\rm 1\;mol\;AgNO_3=1\;mol\;Ag

The given moles of Silver has been 0.854 mol. Thus, the moles of silver nitrate required has been given as:

\rm 1\;mol\;Ag^+=1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;\times\;1\;mol\;AgNO_3\\0.854\;mol\;Ag^+=0.854\;mol\;AgNO_3

The moles of silver nitrate required to form 0.854 mol silver ion has been 0.854 mol.

For more information about the moles produced, refer to the link:

brainly.com/question/10606802

6 0
2 years ago
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