The Sun's gravitational pull keeps our planet orbiting the Sun <span>in a nice nearly-circular orbit.</span>
Answer : The final temperature of gas is 266.12 K
Explanation :
According to the Joule-Thomson experiment, it states that when a gas is expanded adiabatically from higher pressure region to lower pressure region, the change in temperature with respect to change in pressure at constant enthalpy is known as Joule-Thomson coefficient.
The formula will be:

or,

As per question the formula will be:
.........(1)
where,
= Joule-Thomson coefficient of the gas = 
= initial temperature = 
= final temperature = ?
= initial pressure = 200.0 atm
= final pressure = 0.95 atm
Now put all the given values in the above equation 1, we get:


Therefore, the final temperature of gas is 266.12 K
Answer: the sun's rays is one of the raw Materials recquired by plants to make food
Explanation:plants trap light used in splitting water into hydrogen ions and oxygen molecules
Answer:
Core is the layer of the sun is energy transferred between atoms.
Explanation:
Answer:
c. Kinetic energy
Explanation:
The two types of energy involved in this problem are:
- Potential energy: it is the energy possessed by an object due to its position. It is calculated as

where
m is the mass of the object
g is the acceleration due to gravity
h is the height of the object relative to the ground
From the formula, we see that the higher the object is above the ground (higher h), the larger the potential energy of the object. In this problem, the pig is falling down, so the value of h is decreasing, therefore the potential energy is decreasing as well.
- Kinetic energy: it is the energy possessed by an object due to its motion. It is given by:

where
m is the mass of the object
v is its speed
In this problem, as the pig falls down, it accelerates, so its speed increases: since the kinetic energy is proportional to the square of the speed, as the speed increases, its kinetic energy increases too. So, the correct answer is
c. Kinetic energy