Answer:
The equation that will relate all the given parameters, in other to calculate the potential energy of charge A is:
∆V = ∆U/q, ∆V is potential at charge A position, q is magnitude of charge A, ∆U will be made the subject of the relation, which is the Potential Energy of charge A. The notation "∆" show, the quantities have both in values and final values, in the electric field.(Change in Electric potential and potential energy, due to the effect of the field)
Explanation:
The potential energy of a charged particle (Charge A) in an electric field depends on the magnitude of the charge(Known as stated in the question). However, the potential energy per unit charge has a unique value at any point in the electric field.
Answer:
The pacific floor (oceanic crust) is thinner and more denser
Explanation:
The continental crust have a thickness of about 35 to 40 km on an average, and are composed of rocks that has less denser granitic minerals such as feldspar, quartz.
On the other hand, the oceanic crust have a thickness of about 7 to 10 km on an average, and it is comprised of denser mafic rocks that contains high amount of olivine and pyroxene minerals.
Due to this, the oceanic crust subducts below the continental crust during the time of collision.
Thus, the pacific floor (oceanic crust) is thinner and more denser, in comparison to the South American continental crust.
Answer:
The magnetic poles are the places on the earth's surface where the magnetic field force is acting perpendicularly to the surface. The North magnetic pole is where the field is acting straight down; at the South magnetic pole, it is acting straight up.
Explanation:
Answer is B hope this helps
Answer:
3.12 x 10^-5 m
Explanation:
Length of steel column, L = 4 m
diameter, d = 0.2 m
radius = half of diameter = 0.1 m
Young's modulus, Y = 2 x 10^11 N/m^2
Mass of truck, m = 5000 kg
Force, F = mass of truck x acceleration due to gravity
F = 5000 x 9.8 = 49000 N
Area of crossection of cable,
A = 
Let ΔL be the shrink in length of cable, then by the formula of Young's modulus



ΔL = 3.12 x 10^-5 m
Thus, the shrink in the length of cable is 3.12 x 10^-5 m.