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3 years ago

An object is placed at 1.5 m from a convex lens with a focal length of 1.0 m.

1 answer:

8 0

A. Use the thin lens equation to determine the image distance from the lens. Is the correct answer because I have no idea why

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What are two differences between gravity and air resistance

Natalka [10]

1. Air resistance force usually upwards, but gravity doenwards.

2. Objects are affected by gravity the same, but air resistance can affect the speed of an object's descent.

Sorry if im wrong

4 0

3 years ago

Scientists want to place a 3400.0 kg satellite in orbit around Mars. They plan to have the satellite orbit at a speed of 2480.0

BaLLatris [955]

Answer:

Part a)

$r = 6.96 \times 10^6 m$

Part b)

$F_g = 3.004 \times 10^3 N$

Part c)

$a = 0.88 m/s^2$

Part d)

$v = \frac{2480}{2} = 1240 m/s$

Explanation:

Part a)

As we know that the orbital speed of the satellite is given as

$v = 2480 m/s$

now we will have

$v = \sqrt{\frac{GM_{mars}}{r}}$

now we have

$M_{mars} = 6.4191 \times 10^{23} kg$

$R_{mars} = 3.397 \times 10^6 m$

now we have

$2480 = \sqrt{\frac{(6.67 \times 10^{-11})(6.4191 \times 10^{23})}{r}}$

$r = 6.96 \times 10^6 m$

Part b)

Here force between mars and satellite is the gravitational attraction force which is given as

$F_g = \frac{GM_{mars} m}{r^2}$

$F_g = \frac{(6.67\times 10^{-11})(6.4191 \times 10^{23})(3400)}{(6.96\times 10^6)^2}$

$F_g = 3.004 \times 10^3 N$

Part c)

Acceleration of satellite is the ratio of gravitational force and mass of the satellite

$a = \frac{F_g}{m}$

$a = \frac{3004}{3400}$

$a = 0.88 m/s^2$

Part d)

As we know by III law of kepler

$\frac{T_1^2}{T_2^2} = \frac{r_1^3}{r_2^3}$

here we know that T2 = 8 T1

$(\frac{1}{8})^2= \frac{r_1^3}{r_2^3}$

$\frac{r_1}{r_2} = (\frac{1}{2})^2$

so we have

$r_2 = 4r_1$

as we know that speed is given as

$v = \sqrt{\frac{GM}{r}}$

so we can say since radius is orbit becomes 4 times so the orbital speed must be half

$v = \frac{2480}{2} = 1240 m/s$

7 0

4 years ago

After examining a sequence of horizontal sedimentary rocks, a geologist determines that there is a considerable span of time for

WARRIOR [948]

I'm not 100 percent sure but I think the correct answer is B. Disconformity.

6 0

3 years ago

Read 2 more answers

An experimental 1500-kg car travels at a constant speed of 22 m/s around a circular test track that is 80 m across. What is the

stepladder [879]

Answer:

363000 J or 363 kJ

Explanation:

Because the car is not rotating, it has no rotational kinetic energy. Its kinetic energy is then simply

$\frac{1}{2} mv^2 = \frac{1}{2}\times1500\times22^2 = 363000 \text{ J}$

8 0

4 years ago

This person is fishing in a small, freshwater body of water. This body of water flows into a larger body of water called a river

ANEK [815]

Since the small body of water is connected to a larger body of water. so the small body of water will than be called a stream

6 0

4 years ago