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3 years ago

What kind of reaction does Iron (III) and copper (II) sulfate solution produce?

Chemistry

2 answers:

satela [25.4K]3 years ago

6 0

Answer:

Single displacement reaction.

Explanation:

Hello,

In this case, the mentioned chemical reaction turns out:

$Fe^{3+}+CuSO_4\rightarrow Fe_2(SO_4)_3+Cu^{2+}$

Therefore, as the iron is exchanged with the copper, iron (III) sulfate is yielded and copper (II) cations are released to the aqueous solution.

Best regards.

ivanzaharov [21]3 years ago

4 0

Answer:

The answer to your question is Single replacement

Explanation:

Types of reaction in Chemistry

Synthesis two or more reactants combine to produce one single product

Decomposition one reactant splits producing two or more products

Single replacement One element replaces a similar one in a compound.

Double replacement Two compounds interchange their cations and anions.

Combustion one compound reacts with oxygen to produce carbon dioxide and water.

Reaction given

Fe⁺² + CuSO₄ ⇒ Cu + FeSO₄

This is a single replacement reaction

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Complete Question

Questions Diagram is attached below

Answer:

* $W=1142.86Joule$

* $Q=997.7J$

* $H=2140.5J$

Explanation:

From the question we are told that:

Temperature $T=337K$

Pressure $P=(60-55)Pa*10^5$

Volume $V=(1.6-1.4)m^3*10^{-3}$

Generally the equation for gas Constant is mathematically given by

$\frac{P_2}{P_1}=\frac{V_1}{V_2}^n$

$\frac{55*10^5}{60*10^5}=\frac{1.4*10^{-3}}{1.6*10^{-3}}^n$

$n=0.65$

Therefore

Work-done

$W=\int{pdv}$

$W=\frac{55*10^5*1.6*10^{-3}*60*10^5*1.4*10^{-3}}{1-0.65}$

$W=1142.86Joule$

Generally the equation for internal energy is mathematically given by

$Q=mC_vdT\\\\Q=\frac{3*1*3.314*16}{1.4-1}$

$Q=997.7J$

Therefore

$H=Q+W$

$H=997.7J-11.42.9$

$H=2140.5J$

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