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Kobotan [32]
3 years ago
14

A resistor with R = 300 Ω and an inductor are connected in series across an ac source that has voltage amplitude 500 V. The rate

at which electrical energy is dissipated in the resistor is 286 W. What is the impedance Z of the circuit?
Physics
1 answer:
schepotkina [342]3 years ago
3 0

Answer:

Explanation:

impedance z=(XL^2+R^2)^1/2

power across te resistor ==i^2r

286/300

I=.976

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