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Ksenya-84 [330]
3 years ago
11

One plane departed from New York, and at the same time another plane departed from Mexico City. They flew toward each other at r

ate of 650 and 550 mph. If New York and Mexico City are 3000 miles apart, in how many hours did the planes pass each other?
Physics
2 answers:
gayaneshka [121]3 years ago
8 0

Answer:

Explanation:

We also know that, v = S/t which can be rewritten as v * t = S

Where,

v = velocity

S = distance

t = time

i. v1*t = S1

ii. v2*t = S2

iii. s1 + s2 = 3000

Substituting i and ii into equation iii,

St = S1 + S2

v1*t + v2*t = 3000

650*t + 550*t = 3000

1200*t = 3000

t = 3000/1200

t = 2.5 h.

sdas [7]3 years ago
3 0

Answer:

30 hours

Explanation:

Average speed = distance/time

Let the time taken for each plane to pass each other be t

Average speed of plane that left from New York = 650 mph

Distance covered = 650t miles

Average speed of plane that left from Mexico = 550 mph

Distance covered = 550t miles

Distance apart = 3000 miles

650t - 550t = 3000

100t = 3000

t = 3000/100 = 30 hours

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Answer and Explanation:

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3 years ago
How can a 1kg ball have more kinetic energy than a 100kg ball? Explain both using words and by providing a numerical example
MariettaO [177]

1 kg ball can have more kinetic energy than a 100 kg ball as increase in velocity is having greater impact on K.E than increase in mass.

<u>Explanation</u>:

We know kinetic energy can be judged or calculated by two parameters only which is mass and velocity. As kinetic energy is directly proportional to the (velocity)^2 and increase in velocity leads to greater effect on translational Kinetic Energy. Here formula of Kinetic Energy suggests that doubling the mass will double its K.E but doubling velocity will quadruple its velocity:

\text { Kinetic Energy }=\frac{1}{2} m v^{2}

Better understood from numerical example as given:

If a man A having weight 50 kg run with speed 5 m/s and another man B having 100 kg weight run with 2.5 m / s. Which man will have more K.E?

This can be solved as follows:

\text { Kinetic Energy of } \mathrm{A}=\frac{1}{2} 50 \times 5^{2}=625 \mathrm{J}

\text { Kinetic Energy bf } \mathrm{B}=\frac{1}{2} 100 \times 2.5^{2}=312.5 \mathrm{J}

It shows that man A will have more K.E.

Hence 1 kg ball can have more K.E than 100 kg ball by doubling velocity.

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2 years ago
You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is the
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Answer:

Option (c) : 20°C

Explanation:

t(final) =  \frac{w1 \times t1 + w2 \times t2}{w1 + w2}

T(final) = 500* 10 + 100*70/600 = 20°C

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3 years ago
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Masja [62]
The correct answer is A, 2x^3 - x^2 +3x +7

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Calculate the kinetic energy in joules of a ball of mass 40g moving at a velocity of 4 metres per second​
AfilCa [17]
Given : A ball of mass 40 g moving at a velocity of 4 m/s.
To find : Calculate the kinetic energy in joules ?
Solution :
The kinetic energy formula is given by,

where, v is the velocity v=4 m/s
m is the mass m=40 g
Convert g into kg,



Substitute the values,



Therefore, the kinetic energy is 0.32 Joules.
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