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Ksenya-84 [330]
3 years ago
11

One plane departed from New York, and at the same time another plane departed from Mexico City. They flew toward each other at r

ate of 650 and 550 mph. If New York and Mexico City are 3000 miles apart, in how many hours did the planes pass each other?
Physics
2 answers:
gayaneshka [121]3 years ago
8 0

Answer:

Explanation:

We also know that, v = S/t which can be rewritten as v * t = S

Where,

v = velocity

S = distance

t = time

i. v1*t = S1

ii. v2*t = S2

iii. s1 + s2 = 3000

Substituting i and ii into equation iii,

St = S1 + S2

v1*t + v2*t = 3000

650*t + 550*t = 3000

1200*t = 3000

t = 3000/1200

t = 2.5 h.

sdas [7]3 years ago
3 0

Answer:

30 hours

Explanation:

Average speed = distance/time

Let the time taken for each plane to pass each other be t

Average speed of plane that left from New York = 650 mph

Distance covered = 650t miles

Average speed of plane that left from Mexico = 550 mph

Distance covered = 550t miles

Distance apart = 3000 miles

650t - 550t = 3000

100t = 3000

t = 3000/100 = 30 hours

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