Answer:
The height of the building is 88.63 m.
Explanation:
Given;
initial component of vertical velocity, = 12 m/s sin 26° = 5.26 m/s
initial horizontal component of the velocity, = 12 m/s cos 26° =10.786 m/s
horizontal distance traveled by the rock, x = 40.4 m
time of flight is calculated as;
x = t
t = x /
t = 40.4 / 10.786
t = 3.75 s
Determine the final vertical velocity of the ball;
Determine the height of the rock;
Therefore, the height of the building is 88.63 m.
Answer:
The minimum stopping distance when the car is moving at
29.0 m/sec = 285.94 m
Explanation:
We know by equation of motion that,
Where, v= final velocity m/sec
u=initial velocity m/sec
a=Acceleration m/
s= Distance traveled before stop m
Case 1
u= 13 m/sec, v=0, s= 57.46 m, a=?
a = -1.47 m/ (a is negative since final velocity is less then initial velocity)
Case 2
u=29 m/sec, v=0, s= ?, a=-1.47 m/ (since same friction force is applied)
s = 285.94 m
Hence the minimum stopping distance when the car is moving at
29.0 m/sec = 285.94 m