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belka [17]
3 years ago
8

How does increasing the temperature affect collisions?

Chemistry
2 answers:
ddd [48]3 years ago
8 0
Combustion Have a great day!
Nastasia [14]3 years ago
8 0

Answer:

When the temperature is increased, the mean energy of the particles also increases. The frequency of collisions increases, but so does the likelihood that the collision exceeds the activation energy . Both changes mean that the proportion of collisions that are successful increases

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Name 3 things that would be considered a compound.
Afina-wow [57]

Answer:

carbon dioxide, salt, copper

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3 years ago
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What is the final pressure, in mmHg, for a gas in an aerosol can at an initial pressure of 1.40 atm at 12°C which is heated to 3
liubo4ka [24]

Answer:

b. 1150 mmHg

General Formulas and Concepts:

<u>Chemistry - Gas Laws</u>

Gay Lussac Law - \frac{P_1}{T_1} =\frac{P_2}{T_2}

  • P₁ is Pressure 1
  • T₁ is Temperature 1 in Kelvin
  • P₂ is Pressure 2
  • T₂ is Temperature 2 in Kelvin

Explanation:

<u>Step 1: Define</u>

P₁ = 1.40 atm

T₁ = 12°C

P₂ = unknown

T₂ = 35°C

<u>Step 2: Identify Conversions</u>

1 atm = 760 mmHg

K = °C + 273.15

<u>Step 3: Convert</u>

P₁ = 1.40 atm = 1064 mmHg

T₁ = 12°C = 285.15 K

T₂ = 35°C = 308.15 K

<u>Step 4: Find P₂</u>

  1. Substitute:                    \frac{1064 \ mmHg}{285.15 \ K} =\frac{P_2}{308.15 \ K}
  2. Cross-multiply:            (1064 \ mmHg)(308.15 \ K)=P_2(285.15 \ K)
  3. Multiply:                       327872 \ mmHg \cdot K=P_2(285.15 \ K)
  4. Isolate P₂:                    \frac{327872 \ mmHg \cdot K}{285.15 \ K}=P_2
  5. Divide:                         1149.82 \ mmHg=P_2
  6. Rewrite:                       P_2=1149.82 \ mmHg

<u>Step 5: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules and round.</em>

1149.82 mmHg ≈ 1150 mmHg

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3 years ago
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kondaur [170]

Answer:

Decomposition

Explanation:

A decomposition reaction is when a compound breaks down into simpler substances.

in our case Ammonium hydroxide requires an input of energy to obtain Ammonia gas and water.

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<span>insoluble is your answer</span>
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In an atom, where are electrons with less energy most likely located
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Please let me know when you find out, i need this question answered as well
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