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Shalnov [3]
3 years ago
7

Suppose a thick nimbostratus cloud contains ice crystals and cloud droplets all about the same size. Which precipitation process

will be most important in producing rain from this cloud? Why?
Physics
1 answer:
Ronch [10]3 years ago
7 0

Answer:The most important process would be the ice crystal process

Explanation:

Ice crystal process also called Bergeron process requires numerous small water drops that are supercooled, which is a common feature in clouds between about 0° and -20°C or below, along with a small number of ice crystals. Therefore because the collision-coalescence process requires that cloud droplets be of varying size so that drops will fill at different speeds, the most important process would be the ice crystal process.

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Good coding specialists share which of the following characteristics?
Anarel [89]
The correct option is C.
For an individual to become a code specialist, such a person must have advanced computer skills especially in coding processes. The medical field has many sub specialties, therefore a coding specialist must choose to work in a particular area of medicine which interest him most. Such people must also be able to work independently.
5 0
3 years ago
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Consider a car that travels between points A and B. The car's average speed can be greater than the magnitude of its average vel
ryzh [129]

Answer: A.True

Explanation: simply put the magnitude of the speed is a function of Distance while the magnitude of velocity is a function of Displacement. Displacement is the average Distance moved in different directions which will be smaller in magnitude compared to the Total Distance used the calculating the magnitude of speed.

4 0
3 years ago
An object at rest starts accelerating.
Shalnov [3]

Answer:

<u>We are given: </u>

initial velocity (u) = 0 m/s

final velocity (v) = 10 m/s

displacement (s) = 20 m

acceleration (a) = a m/s/s

<u>Solving for 'a'</u>

From the third equation of motion:

v² - u² = 2as

replacing the variables

(10)² - (0)² = 2(a)(20)

100 = 40a

a = 100 / 40

a = 2.5 m/s²

6 0
3 years ago
Suppose a particle moves along a straight line with velocity v(t)=t2e−2tv(t)=t2e−2t meters per second after t seconds. How many
dimulka [17.4K]

Explanation:

It is given that,

Velocity of the particle moving in straight line is :

v(t)=t^2e^{-2t}\ m/s

We need to find the distance (x)  traveled by the particle during the first t seconds. It is given by :

x=\int\limits {v.dt}

x=\int\limits {t^2e^{-2t}dt}

Using by parts integration, we get the value of x as :

x=\dfrac{-(2t^2+2t+1)e^{-2t}}{4}\ meters

Hence, this is the required solution.

6 0
4 years ago
Displacement vectors of 4km north, 2km south, 5km north, 5km south combine to a total displacement of
goldfiish [28.3K]

<u>Answer</u>

The combined displacement is 2km north


<u>Explanation</u>


Since displacement is a vector quantity, we take into account the direction.


Good for us all the displacement vectors are in the same dimension, so we can make north positive and south negative or vice-versa.


We now add to obtain,

4+-2+5+-5

This will simplify to

=4-2+5-5=2

Therefore the combined displacement is 2km north

5 0
3 years ago
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