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3 years ago

WHAT IS THE MASS OF AN OBJECT WHOSE DENSITY IS 0.23 G/ML AND A VOLUME OF 22.5 ML?

Chemistry

1 answer:

7nadin3 [17]3 years ago

4 0

Answer:

<h2>The answer is 5.18 g</h2>

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume = 22.5 mL

density = 0.23 g/mL

We have

mass = 0.23 × 22.5 = 5.175

We have the final answer as

Hope this helps you

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- How much power does it take to lift a<br> 1,000 N load 10 m in 20 s?

Mariana [72]

Answer:

"500 Joule/sec" is the right answer.

Explanation:

The given values are:

Force,

F = 1000 N

Velocity,

s = 10 m

Time,

t = 20 s

Now,

The power will be:

= $\frac{Force\times Velocity}{Time}$

On putting the values, we get

= $\frac{1000\times 10}{20}$

= $\frac{10000}{20}$

= $500 \ Joule/sec$

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3 years ago

How to calculate from moles to grams?<br> 4.0 moles of Cu(CN)2

andreyandreev [35.5K]

Answer: The mass of given amount of copper (II) cyanide is 462.4 g

Explanation:

To calculate the number of moles, we use the equation:

We are given:

Moles of copper (II) cyanide = 4 moles

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Putting values in above equation, we get:

Hence, the mass of given amount of copper (II) cyanide is 462.4 g

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2 years ago

A wooden tool is found at an archaeological site. Estimate the age of the tool using the following information: A 100 gram sampl

lord [1]

Answer:

2578.99 years

Explanation:

Given that:

100 g of the wood is emitting 1120 β-particles per minute

Also,

1 g of the wood is emitting 11.20 β-particles per minute

Given, Decay rate = 15.3 % per minute per gram

So,

Concentration left can be calculated as:-

C left = $[A_t]=\frac{11.20\ per\ minute}{15.3\ per\ minute\ per\ gram}\times [A_0]= 0.7320[A_0]$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Also, Half life of carbon-14 = 5730 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac {ln\ 2}{t_{1/2}}$

$k=\frac {ln\ 2}{5730}\ years^{-1}$

The rate constant, k = 0.000120968 year⁻¹

Time =?

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

So,

$\frac {[A_t]}{[A_0]}=e^{-0.000120968\times t}$

$\frac {0.7320[A_0]}{[A_0]}=e^{-0.000120968\times t}$

$0.7320=e^{-0.000120968\times t}$

$ln\ 0.7320=-0.000120968\times t$

<u>t = 2578.99 years</u>

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3 years ago

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We found cesium, strontium, aluminum, sulfur, chlorine, and fluorine on the periodic table. Cesium is the farthest left and the lowest, while fluorine is the farthest right and the highest, so we know they have the highest metallic character and the lowest metallic character, respectively.

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