Answer:
The [H⁺] for this soluton is 2*10⁻³ M
Explanation:
pH, short for Hydrogen Potential and pOH, or OH potential, are parameters used to measure the degree of acidity or alkalinity of substances.
The values that compose them vary from 0 to 14 and the pH value can be directly related to that of pOH by means of:
pH + pOH= 14
In this case, pOH=11.30, so
pH + 11.30= 14
Solving:
pH= 14 - 11.30
pH= 2.7
Mathematically the pH is the negative logarithm of the molar concentration of the hydrogen or proton ions (H⁺) or hydronium ions (H₃O):
´pH= - log [H⁺] = -log [H₃O]
Being pH=2.7:
2.7= - log [H⁺]
[H⁺]= 10⁻² ⁷
[H⁺]=1.995*10⁻³ M≅ 2*10⁻³ M
<u><em>The [H⁺] for this soluton is 2*10⁻³ M</em></u>
<h2>
Answer:</h2>
Option A is correct.
<h3>Explanation:</h3>
In the options given below the isomer given in the option A of 1-tert-butyl-5-methylcyclohexane is the most stable of all. The IUPAC name for this compound is 1-tert-butyl-3-ethyl-5-methylbenzene.
Answer: It is a basic solution with pH =8.51
Explanation:
We were given that hydroxide ion concentration [OH-] as 3.26 x 10-6 M
But We know thar
[OH-] [H+] = 1 × 10^-14
To get the Hydrogen ion [H+] concentration, we have that
[H+] = 1 × 10^-14 M/[OH-]
= 1 × 10^-14 M/3.26 x 10-6 M
= 3.067 x 10^-9 M
But, pH = - log [H+]
Therefore,
pH = - log (3.067 x 10^-9)
pH=8.51
when pH > 7, The solution is basic, therefore a solution with pH =8.51 is basic.
Answer:
[MCHM] = 7.52 M
Explanation:
This all about unit conversion
1 feet = 0.3048 meters
1 yard = 0.9144 meters
7.60 feet . 0.3048 = 2.31 meters deep
100 yd . 0.9144 meters = 91.44 meters long and 91.44 meters wide
In the river we have a volume of:
2.31 m . 91.44m . 91.44m = 19314.5 m³
1 dm³ = 1 L
1 dm³ = 0.001 m³
19314.5 m³ / 0.001 m³ = 19314542 L (The final volume of the river)
3.785 L = 1 gallon
In 19314542 L, we have (19314542 / 3.785) = 5102917 gallons
1 gallon = 128 oz
5102917 gallons . 128 = 653173376 oz
1 oz = 28.3495 g
653173376 oz . 28.495 = 1.86x10¹⁰ grams
Molar mass MCHM = 128 g/m
Moles of MCHM = 1.86x10¹⁰ grams / 128 g/m = 145312500 moles
Molarity = mol /L → 145312500 moles / 19314542 L = 7.52 M
