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Firlakuza [10]
3 years ago
11

A car advertisement states that a certain car can accelerate from rest to

Physics
1 answer:
Evgen [1.6K]3 years ago
5 0

Answer:

8 km/h²

Explanation:

a = v-u/t

v is final velocity, u is initial velocity

a = 40-0/5

a = 8.0 km/h²

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Which of the following would be an example of basic research?
lara [203]

Answer: Experimenting to determine the fundamental properties of x-rays.

Explanation:

Scientific basic research aims to find the fundaments or principles of the phenomena.

The basic research is intended to understand the matter, its nature, its properties, its behavior. It searches to make theory. To finding how the things work but not how to use those things for a determined purpose.

The study of the properties of the atom to understand what it is, how it interacts with other atoms, how it determines the properties of the matter are some examples of basic research, such as experimenting to determine the fundamental properties of x-rays is.

On the other hand, the other examples given, Spencer's research on WWII radar technology that led to the invention of the microwave oven, Edison's research and use of other scientists' work to invent the light bulb, and Morrison and Franscioni's research done to create the Frisbee, are examples of applied research science. This is research to find a valuable use of some scientific knowledge.


6 0
4 years ago
Read 2 more answers
A 0.023 kg beetle is sitting on a record player 0.15 m from the center of the record. if it takes 0.070 n of force to keep the b
Margaret [11]
The answer is 0.68 meters per second, swagteam
6 0
4 years ago
Read 2 more answers
Pages 64 to 65 of your reading material trace an extended problem that involes lifting a bag of sugar up to a shelf at first it
nadezda [96]

Answer:

d) the amount of work is the same whether the bag is moved all at once or in two stages, provided the total height lifted is the same in either case.

Explanation:

While moving the bag to the shelf in one shot we can say that the total work done is given as

W = mg(2H)

here we know that

2H = total height raised by the bag

now when we raise the bag to first shelf and then move it to next shelf

then we will have

W = W_1 + W_2[tex][tex]W = mgH + mgH

W = 2mgH

so the correct answer will be

d) the amount of work is the same whether the bag is moved all at once or in two stages, provided the total height lifted is the same in either case.

7 0
3 years ago
How many times bigger is the radius of a helium atom then the radius of an alpha particle
kiruha [24]

The radius of a helium atom 4.8 times bigger  then the radius of an alpha particle.

<h3>What is alpha particle?</h3>

The structure of alpha particles, also known as alpha rays and alpha radiation, is similar to that of the helium-4 nucleus and has been made up of two protons as well as two neutrons bonded together.

<h3>What is helium?</h3>

For welding metals like aluminum, helium was utilized as an inert gas environment. It is also employed in rocket propulsion.

The radius of a helium atom 4.8 times bigger  then the radius of an alpha particle. More precisely than it's ever been, the diameter of the helium atom's nucleus, the alpha particle, had also been measured. Outcomes just point to a size of 1.6782 femtometers, 4.8 times more accurate than earlier readings.

To know more about helium  and alpha particle.

brainly.com/question/2288334

#SPJ3

4 0
2 years ago
A river 500 ft wide flows with a speed of 8 ft/s with respect to the earth. A woman swims with a speed of 4 ft/s with respect to
White raven [17]

Answer:

1) \Delta s=1000\ ft

2)  \Delta s'=998.11\ ft.s^{-1}

3) t\approx125\ s

t'\approx463.733\ s

Explanation:

Given:

width of river, w=500\ ft

speed of stream with respect to the ground, v_s=8\ ft.s^{-1}

speed of the swimmer with respect to water, v=4\ ft.s^{-1}

<u>Now the resultant of the two velocities perpendicular to each other:</u>

v_r=\sqrt{v^2+v_s^2}

v_r=\sqrt{4^2+8^2}

v_r=8.9442\ ft.s^{-1}

<u>Now the angle of the resultant velocity form the vertical:</u>

\tan\beta=\frac{v_s}{v}

\tan\beta=\frac{8}{4}

\beta=63.43^{\circ}

  • Now the distance swam by the swimmer in this direction be d.

so,

d.\cos\beta=w

d\times \cos\ 63.43=500

d=1118.034\ ft

Now the distance swept downward:

\Delta s=\sqrt{d^2-w^2}

\Delta s=\sqrt{1118.034^2-500^2}

\Delta s=1000\ ft

2)

On swimming 37° upstream:

<u>The velocity component of stream cancelled by the swimmer:</u>

v'=v.\cos37

v'=4\times \cos37

v'=3.1945\ ft.s^{-1}

<u>Now the net effective speed of stream sweeping the swimmer:</u>

v_n=v_s-v'

v_n=8-3.1945

v_n=4.8055\ ft.s^{-1}

<u>The  component of swimmer's velocity heading directly towards the opposite bank:</u>

v'_r=v.\sin37

v'_r=4\sin37

v'_r=2.4073\ ft.s^{-1}

<u>Now the angle of the resultant velocity of the swimmer from the normal to the stream</u>:

\tan\phi=\frac{v_n}{v'_r}

\tan\phi=\frac{4.8055}{2.4073}

\phi=63.39^{\circ}

  • Now let the distance swam in this direction be d'.

d'\times \cos\phi=w

d'=\frac{500}{\cos63.39}

d'=1116.344\ ft

<u>Now the distance swept downstream:</u>

\Delta s'=\sqrt{d'^2-w^2}

\Delta s'=\sqrt{1116.344^2-500^2}

\Delta s'=998.11\ ft.s^{-1}

3)

Time taken in crossing the rive in case 1:

t=\frac{d}{v_r}

t=\frac{1118.034}{8.9442}

t\approx125\ s

Time taken in crossing the rive in case 2:

t'=\frac{d'}{v'_r}

t'=\frac{1116.344}{2.4073}

t'\approx463.733\ s

7 0
4 years ago
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