Answer:
1.034m/s
Explanation:
We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,
<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,
Substituting,
Part B)
For the Part B we need to apply conserving momentum equation, this formula is given by,
Where here is the velocity after the collision.
The answer is C, 50J
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Answer:
R = 1.79*10^6 Ω
C = 2.46*10^-6 F
Explanation:
Given
emf of the source, ε = 120 V
Current passing through the resistor, I = 6.7*10^-5 A
Time constant for the circuit, τ = 4.4 s
From the information above, we can say that RC = 4.4 s
Also, on applying the loop rule, we get
ε - IR = 0
ε = IR
R = ε / I
R = 120 / 6.7*10^-5
R = 1.79*10^6 Ω
Using the first equation, we can thus solve for C
RC = 4.4 s
C = 4.4 / R
C = 4.4 / 1.79*10^6
C = 2.46*10^-6 F
C = 2.46 μF
Therefore, the resistance and capacitance of the capacitor is respectively, 1.79 MΩ and 2.46 μF