Mass of PH3= 6.086 g
<h3>Further explanation</h3>
Given
6.0 L of H2
Required
mass of PH3
Solution
Reaction
P4 + 6H2 → 4PH3
Assumed at STP ( 1 mol gas=22.4 L)
Mol of H2 for 6 L :
= 6 : 22.4 L
= 0.268
From the equation, mol PH3 :
= 4/6 x moles H2
= 4/6 x 0.268
= 0.179
Mass PH3 :
= 0.179 x 33,99758 g/mol
= 6.086 g
If one or more nucleotide pairs are deleted from a DNA strand, this is known as a frameshift mutation
<h3>
Define Frameshift Mutation</h3>
Insertions or deletions in the genome that are not multiples of three nucleotides are referred to as frameshift mutations. They are a particular class of insertion-deletion (indel) alterations that are present in polypeptides' coding sequences. Here, there are no multiples of three in the number of nucleotides that are added to or subtracted from the coding sequence. They may result from really basic alterations like the insertion or deletion of a single nucleotide.
<h3>
Frameshift mutations' effects</h3>
One of the most harmful modifications to a protein's coding sequence is a frameshift mutation. They are quite prone to produce non-functional proteins that frequently interfere with a cell's metabolic processes and result in significant alterations to polypeptide length and chemical makeup. Frameshift mutations can cause the mRNA to stop translating too soon and create an extended polypeptide.
Learn more about Frameshift mutations here:-
brainly.com/question/12732356
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Solution :
From the balanced chemical equation, we can say that 1 moles of KBr will produce 1 moles of KCl .
Moles of KBr in 102 g of potassium bromide.
n = 102/119.002
n = 0.86 mole.
So, number of miles of KCl produced are also 0.86 mole.
Mass of KCl produced :
Hence, this is the required solution.
Answer:
0.733 mol.
Explanation:
- From the balanced equation:
<em>2Fe₂O₃ + C → Fe + 3CO₂,</em>
It is clear that 1.0 moles of Fe₂O₃ react with 1.0 mole of C to produce 1.0 mole of Fe and 3.0 moles of CO₂.
- Since Fe₂O₃ is in excess, C will be the limiting reactant.
<u><em>Using cross multiplication:</em></u>
1.0 mole of C produces → 3.0 moles of CO₂, from the stichiometry.
??? mole of C produces → 2.2 moles of CO₂.
∴ The no. of moles of C needed to produce 2.2 moles of CO₂ = (1.0 mole of C) (2.2 mole of CO₂) / (3.0 mole of CO₂) = 0.733 mol.
Explanation:
firstly find for the molar mass of kcl and molar mass of k
and then
molar mass of k = x
molar mass of kcl= 40
cross mutiply and then simplify you will get your answer
