Answer:
It has denatured
Explanation:
When the temperature get high the enzymes tend to change shape and denaturing occurs.
Answer : The ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2
Explanation :
The relation between the equilibrium constant and standard Gibbs free energy is:
![\Delta G^o=-RT\times \ln Q\\\\\Delta G^o=-RT\times \ln (\frac{[A]_{inside}}{[A]_{outside}})](https://tex.z-dn.net/?f=%5CDelta%20G%5Eo%3D-RT%5Ctimes%20%5Cln%20Q%5C%5C%5C%5C%5CDelta%20G%5Eo%3D-RT%5Ctimes%20%5Cln%20%28%5Cfrac%7B%5BA%5D_%7Binside%7D%7D%7B%5BA%5D_%7Boutside%7D%7D%29)
where,
= standard Gibbs free energy = -14.1 kJ/mol
R = gas constant = 8.314 J/K.mol
T = temperature = 
Q = reaction quotient
= concentration inside the cell
= concentration outside the cell
Now put all the given values in the above formula, we get:
![-14.1\times 10^3J/mol =-(8.314J/K.mol)\times (298K)\times \ln (\frac{[A]_{inside}}{[A]_{outside}})](https://tex.z-dn.net/?f=-14.1%5Ctimes%2010%5E3J%2Fmol%20%3D-%288.314J%2FK.mol%29%5Ctimes%20%28298K%29%5Ctimes%20%5Cln%20%28%5Cfrac%7B%5BA%5D_%7Binside%7D%7D%7B%5BA%5D_%7Boutside%7D%7D%29)
![\frac{[A]_{inside}}{[A]_{outside}}=296.2](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5D_%7Binside%7D%7D%7B%5BA%5D_%7Boutside%7D%7D%3D296.2)
Thus, the ratio of the concentration of substance A inside the cell to the concentration outside is, 296.2
The answer would be A from what I know
Answer: 4.46 x 10^-4M
Explanation:
The pH of a solution is the concentration of hydrogen ion concentration in the solution. Mathematically, it is expressed as pH = -log(H+), where H+ is the concentration of hydrogen ion
On the pH scale, readings are from 1 to 14.
- pH values less than 7 are regarded as acidic. So, the solution with pH 3.35 is said to be acidic, and will produce hydrogen ions.
3.35 = -log(H+)
(H+) = Antilog (-3.35)
(H+) = 0.000446M
Place (H+) in standard form
(H+) = 4.46 x 10^-4M
Thus, the concentration of hydrogen ion in the solution with pH 3.35 is 4.46 x 10^-4M