Answer:
c = 250.58 J/kg/
Explanation:
The specific heat of a substance is the required quantity of heat to increase or decrease the temperature of its unit mas by 1 kelvin.
Q = mcΔθ
where: Q is the quantity of heat absorbed or released, m is the mass of the substance, c is its specific heat and Δθ is the change in temperature of the substance.
Given that; m = 1.0 kg, Q = 1303 J and Δθ = 5.2 , then;
c = Q ÷ (mΔθ)
= 1303 ÷ (1.0 × 5.2)
= 1303 ÷ 5.2
= 250.58 J/kg/
The specific heat of the object is 250.58 J/kg/.
Answer: 8.24x10^5 years, or 8.24x10^3 centuries
Explanation: Sequential conversions to arrive at a total population rate of 2.31x10^10 atoms/sec for the entire population. Total seconds would be (6.02x10^23 atoms/2.31x10^10 atoms/sec) = 2.60x10^13 seconds. No breaks allowed, then (2.60x10^13 seconds)/(3.1536x10^7 sec/year)= 8.24x10^5 years.
