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bezimeni [28]
3 years ago
7

A 1.0 kg object absorbs 1,303 J of heat energy and experiences a temperature increase of 5.2∘C. What is the object’s specific he

at, in joules per gram-degree celsius? Report your answer with the correct number of significant figures.
Chemistry
2 answers:
KATRIN_1 [288]3 years ago
8 0

Answer:

0.25

Explanation:

konstantin123 [22]3 years ago
5 0

Answer:

c = 250.58 J/kg/^{0}C

Explanation:

The specific heat of a substance is the required quantity of heat to increase or decrease the temperature of its unit mas by 1 kelvin.

Q = mcΔθ

where: Q is the quantity of heat absorbed or released, m is the mass of the substance, c is its specific heat and Δθ is the change in temperature of the substance.

Given that; m = 1.0 kg, Q = 1303 J and Δθ = 5.2 ^{0}C, then;

c = Q ÷ (mΔθ)

  = 1303 ÷ (1.0 × 5.2)

  = 1303 ÷ 5.2

  = 250.58 J/kg/^{0}C

The specific heat of the object is 250.58 J/kg/^{0}C.

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John Dalton made some hypothesis about the structure of atom. He proposed that matter is composed of great number of indivisible particles called atoms they can neither be destroyed nor be created.

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I am guessing that your solutions of HCl and of NaOH have approximately the same concentrations. Then the equivalence point will occur at pH 7 near 25 mL NaOH.

The steps are already in the correct order.

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Answer:

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Explanation:

Hi:

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