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bezimeni [28]
2 years ago
7

A 1.0 kg object absorbs 1,303 J of heat energy and experiences a temperature increase of 5.2∘C. What is the object’s specific he

at, in joules per gram-degree celsius? Report your answer with the correct number of significant figures.
Chemistry
2 answers:
KATRIN_1 [288]2 years ago
8 0

Answer:

0.25

Explanation:

konstantin123 [22]2 years ago
5 0

Answer:

c = 250.58 J/kg/^{0}C

Explanation:

The specific heat of a substance is the required quantity of heat to increase or decrease the temperature of its unit mas by 1 kelvin.

Q = mcΔθ

where: Q is the quantity of heat absorbed or released, m is the mass of the substance, c is its specific heat and Δθ is the change in temperature of the substance.

Given that; m = 1.0 kg, Q = 1303 J and Δθ = 5.2 ^{0}C, then;

c = Q ÷ (mΔθ)

  = 1303 ÷ (1.0 × 5.2)

  = 1303 ÷ 5.2

  = 250.58 J/kg/^{0}C

The specific heat of the object is 250.58 J/kg/^{0}C.

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Which macromolecules were present in the albumin?
bagirrra123 [75]
The answer is proteins.

Albumin is a protein produced in the liver. It belongs to the great family of globular proteins. Since it is the protein, the only macromolecule present in the albumin can be only protein.
5 0
2 years ago
thyroxine an important hormone that controls the rate of metabolism in the body, can be isolated from the thyroid gland. When 0.
Murrr4er [49]

Answer: Molar mass of thyroxine is 776.5 g/mol.

Explanation:

\Delta T_f=K_f\times m

Mass of thyroxine = 0.455 g

Mass of benzene = 10g =0.01kg   (1 kg = 1000 g)

Formula used :  

Delta T_f=K_f\times\frac{\text{Mass of thyroxine}}{\text{Molar mass of thyroxine}\times \text{Mass of benzene in Kg}}

where,

\Delta T_f = change in freezing point = 0.300oC

K_f = freezing point constant = 5.12°Ckg/mol

m = molality

Now put all the given values in this formula, we get

0.300^0C=5.12^0Ckg/mol\times \frac{0.455g}}{\text{Molar mass of thyroxine}\times {0.01kg}

{\text{Molar mass of thyroxine}}=776.5g

Thus  molar mass of thyroxine is 776.5 g/mol.

3 0
2 years ago
Ok, got it!!! thank you so much
bekas [8.4K]
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7 0
2 years ago
The function of the cilia and flagella are:
Tom [10]

Answer:

The last one, to swim

Explanation:

The function of cilia and flagella move liquid past the surface of the cell. For single cells, such as sperm, this enables them to swim. For cells anchored in a tissue, like the epithelial cells lining our air passages, this moves liquid over the surface of the cell (e.g., driving particle-laden mucus toward the throat).

3 0
2 years ago
If the solvent-solute interactions in a mixture are the solvent-solvent interactions and the solute-solute interactions, a homog
andre [41]

Answer:

                 a)  If the solvent-solute interactions in a mixture are <u>stronger than</u> the solvent-solvent interactions and the solute-solute interactions, a homogeneous solution forms.

                 b) If the solvent-solute interactions in a mixture are <u>weaker than</u> the solvent-solvent interactions and the solute-solute interactions, the formation of a homogeneous solution is uncertain.

Explanation:

                     The solubility of solute in given solvent mainly depends upon the intermolecular interactions between the solvent and the solute. If the solute is surrounded and solvated by the solvent then the solute will dissolve in that solvent. Therefore, in order to dissolve the solute must form stronger interactions with the solvent as compared to the solute solute interactions or solvent solvent interactions.

Example:

              When NaCl is added to water the partial negative oxygen of water is attracted to Na⁺ of NaCl and the partial positive hydrogen of water is attracted to Cl⁻ of NaCl. These new interactions between the NaCl ions and water are stronger than the interactions between water molecules and NaCl molecules themselves hence, results in solubility of NaCl in water.

               On the other hand, if NaCl is added to Hexane (C₆H₁₄) it fails to make strong interactions with the solvent molecules resulting in insolubility of NaCl in hexane.

7 0
2 years ago
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