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3 years ago

How many moles of calcium carbonate-CaCO3 = 4.15 g

Chemistry

1 answer:

marin [14]3 years ago

3 0

Answer:

Number of moles = 0.042 mol

Explanation:

Given data:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass/ molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12+ 3×16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol

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KonstantinChe [14]

Because the intention is to boil the solution, the purpose of the solvent is to dissolve so it has a higher boiling point so ensure it stays in liquid form and doesn't evaporate into a gas

also, a pure solvent is made of 1 substance so it has 1 boiling point and the solution must evaporate/boil first

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3 years ago

Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. The volume of gas collected is

Leya [2.2K]

The mass of oxygen collected from the thermal decomposition of potassium chlorate at a temperature of 297 K and 762 mmHg is 0.16 g

<h3>How to determine the mole of oxygen produced </h3>

We'll begin by obtaining the number of mole of oxygen gas produced from the reaction. This can be obtained by using the ideal gas equation as illustrated below:

Volume (V) = 0.128 L
Temperature (T) = 297 K
Pressure (P) = 762 – 22.4 = 739.6 mmHg
Gas constant (R) = 62.363 mmHg.L/Kmol
Number of mole (n) =?

PV = nRT

739.6 × 0.128 = n × 62.363 × 297

Divide both sides by 62.363 × 297

n = (739.6 × 0.128) / (62.363 × 297)

n = 0.0051 mole

Thus, the number of mole of oxygen gas produced is 0.0051 mole

<h3>How to determine the mass of oxygen collected</h3>

Haven obtain the number of mole of oxygen gas produced, we can determine the mass of the oxygen produced as follow:'

Mole = 0.0051 mole
Molar mass of oxygen gas = 32 g/mole
Mass of oxygen =?

Mole = mass / molar mass

0.0051 = mass of oxygen / 32

Cross multiply

Mass of oxygen = 0.0051 × 32

Mass of oxygen = 0.16 g

Thus, we can conclude that the mass of oxygen gas collected is 0.16 g

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1 year ago

A 800N mountain climber scales a 160m cliff. How much work is done by the mountain climber?

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Answer:

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Explanation:

Given that,

Weight of a mountain climber, F = 800 N

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We need to find the work done by the mountain climber. The work done by an object is given by the formula as follows :

W = Fd

Put the values of F and d.

W = 800 N × 160 m

W = 128000 J

W = 128 kJ

So, 128 kJ of work is done by the mountain climber.

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2 years ago

A volume of 125 mL of H2O is initially at room temperature (22.00 ∘C). A chilled steel rod at 2.00 ∘C is placed in the water. If

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Answer:

41.9 g

Explanation:

We can calculate the heat released by the water and the heat absorbed by the steel rod using the following expression.

Q = c × m × ΔT

where,

c: specific heat capacity

m: mass

ΔT: change in temperature

If we consider the density of water is 1.00 g/mol, the mass of water is 125 g.

According to the law of conservation of energy, the sum of the heat released by the water (Qw) and the heat absorbed by the steel (Qs) is zero.

Qw + Qs = 0

Qw = -Qs

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3 years ago

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3 years ago

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How many moles of calcium carbonate-CaCO3 = 4.15 g​

How many moles of calcium carbonate-CaCO3 = 4.15 g