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3 years ago

How many moles of calcium carbonate-CaCO3 = 4.15 g

Chemistry

1 answer:

marin [14]3 years ago

3 0

Answer:

Number of moles = 0.042 mol

Explanation:

Given data:

Number of moles = ?

Mass of calcium carbonate = ?

Solution:

Formula:

Number of moles = mass/ molar mass

now we will calculate the molar mass of calcium carbonate.

atomic mass of Ca = 40 amu

atomic mass of C = 12 amu

atomic mass of O = 16 amu

CaCO₃ = 40 + 12+ 3×16

CaCO₃ = 40 + 12+48

CaCO₃ = 100 g/mol

Now we will calculate the number of moles.

Number of moles = 4.15 g / 100 g/mol

Number of moles = 0.042 mol

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How many moles of calcium carbonate-CaCO3 = 4.15 g​

How many moles of calcium carbonate-CaCO3 = 4.15 g